It is (1+2+2+3-1+7+2+5)/8 = 21/8 = 2.625
Chat with our AI personalities
There are 64 subsets, and they are:{}, {A}, {1}, {2}, {3}, {4}, {5}, {A,1}, {A,2}, {A,3}, {A,4}, {A,5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3, 5}, {4,5}, {A, 1, 2}, {A, 1, 3}, {A, 1, 4}, {A, 1, 5}, {A, 2, 3}, {A, 2, 4}, {A, 2, 5}, {A, 3, 4}, {A, 3, 5}, {A, 4, 5}, {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}, {A, 1, 2, 3}, {A, 1, 2, 4}, {A, 1, 2, 5}, {A, 1, 3, 4}, {A, 1, 3, 5}, {A, 1, 4, 5}, {A, 2, 3, 4}, {A, 2, 3, 5}, {A, 2, 4, 5}, {A, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}, {A, 1, 2, 3, 4}, {A, 1, 2, 3, 5}, {A, 1, 2, 4, 5}, {A, 1, 3, 4, 5}, {A, 2, 3, 4, 5}, {1, 2, 3, 4, 5} {A, 1, 2, 3,,4, 5} .
5/(√3 - 1)= 5(√3 + 1)/(√3 - 1)(√3 + 1)= (5√3 + 5)/[(√3)2 - 12)= (5√3 + 5)/(3 - 1)= 5√3 + 5)/2= 5√3/2 + 1/2
3 ÷ 2/5 = 3/1 ÷ 2/5 = 3/1 × 5/2 = (3×5)/(1×2) = 15/2 = 7½
(3 1/5) - (1 3/5) : If we borrow 1 from 3, then 3 1/5 becomes 2 6/5 [1 = 5/5, and 1/5+5/5 = 6/5]. Now can subtract 3/5 from 6/5, and subtract 1 from 2:6/5 - 3/5 = 3/5. 2-1 = 1. So the answer is 1 3/5.
2==5 and 5!=3 or (5-2)^2>=1
1 5/2 - 3/2 = (5-3)/2 = 2/2 = 1
Who: DixieLocation: Hotton, Desert IsleKeystrokes:1, 3, 2, 4, 3, 5, 4, 6, 5, 7, 6, 8, 8, 6,7, 5, 6, 4, 5, 3, 4, 2, 3, 1, 1Who: ElainaLocation: Wington, Bird IsleKeystrokes:3, 2, 1, 2, 3, 3, 3, 2, 2, 2, 3, 5, 5, 3,2, 1, 2, 3, 3, 3, 3, 2, 2, 3, 2, 1Who: HeinrichLocation: Chillton, Snow IsleKeystrokes:5, 3, 2, 1, 2, 3, 5, 3, 2, 1, 2, 3, 5, 3,5, 6, 3, 6, 5, 3, 2, 1Who: InaraLocation: Appleton, Horse IsleKeystrokes:3, 3, 4, 5, 5, 4, 3, 2, 1, 1, 2, 3, 3, 2, 2,3, 3, 4, 5, 5, 4, 3, 2, 1, 1, 2, 3, 2, 1, 1Who: JasperLocation: Earton, Horse IsleKeystrokes:1, 2, 3, 4, 5, 6, 7, 8Who: KyleighLocation: Witherton, Rider IsleKeystrokes:3, 3, 5, 3, 2, 3, 1, 5, 5, 6, 5, 4, 5, 2, 8,7, 6, 5, 4, 3, 2, 5, 3, 2, 3, 1Who: SandraLocation: Flipperton, Dolphin IsleKeystrokes:1, 1, 2, 1, 2, 3, 2, 3, 4, 3, 4, 5, 4, 5, 6, 5,6, 7, 6, 7, 8, 5, 3, 1Who: SorenLocation: Crystalton, Ice IsleKeystrokes:3, 5, 3, 2, 1, 3, 5, 3, 2, 1, 2, 3, 4, 5,6, 5, 4, 3, 2Who: VeronicaLocation: Shellton, Turtle IsleKeystrokes:3, 2, 1, 3, 2, 1, 5, 4, 4, 3, 5, 4, 4, 3, 5, 8, 8,7, 6, 7, 8, 5, 5, 5, 8, 8, 7, 6,7 8, 5, 5, 4, 3, 2, 1Who: YancyLocation: Treeton, Horse IsleKeystrokes:1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1, 5, 5, 4, 4, 3, 3,2, 5, 5, 4, 4, 3, 3, 2, 1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1
1 2/3=5/3 (2/3)/(5/3)=(2/3)*(3/5)=2/5
2: 1 and 2 3: 1 and 3 5: 1 and 5
The sample space is the following set: {(1. 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2. 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3. 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4. 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5. 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6. 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
3 1/2
There are 32 possible subset from the set {1, 2, 3, 4, 5}, ranging from 0 elements (the empty set) to 5 elements (the whole set): 0 elements: {} 1 element: {1}, {2}, {3}, {4}, {5} 2 elements: {1, 2}, {1, 3}, {1, 4}, {1, 5}, {2, 3}, {2, 4}, {2, 5}, {3, 4,}, {3, 5}, {4, 5} 3 elements: {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5} 4 elements: {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5} 5 elements: {1, 2, 3, 4, 5} The number of sets in each row above is each successive column from row 5 of Pascal's triangle. This can be calculated using the nCr formula where n = 5 and r is the number of elements (r = 0, 1, ..., 5). The total number of subset is given by the sum of row 5 of Pascal's triangle which is given by the formula 2^row, which is this case is 2^5 = 32.