sin-1(a/s) where a = altitude and s = side.
Given ABE, ADC, BD bisescts angle ABC and BD is parallel to EC prove: Triangle EBC is isoceles
Assuming the lengths of the sides are given, then perimetrer = base + 2*leg If the sides are not given, then the answer will depend on what information is provided.
Isoceles triangular * * * * * Any triangle. Congruence is a relationship between two figures. Given any triangle you can always find another that it is congruent to.
It is an isosceles triangle and the 3rd angle is 72 degrees.
In a right triangle, the side opposite the given acute angle is the one that does not touch the angle and is directly across from it. The adjacent side is the one that is next to the angle and forms part of the angle along with the hypotenuse. To identify these sides, visualize the triangle and label the right angle, the acute angle, and then observe which sides are opposite and adjacent to the acute angle.
The dimensions given fit that of a right angle triangle
It depends on the details of the specific triangle.
No because the given dimensions do not comply with Pythagoras; theorem for a right angle triangle.
The Hypotenuse.
Yes the given dimensions complies with Pythagoras' theorem for a right angle triangle.
An equilateral triangle would fit the given description
BAD = BCD is the answer i just did it