Want this question answered?

Q: What is the base for a triangle that has a high of 14.2 inches in an area of 63.9 inches?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

The height has not been given but the area of the triangle is: 0.5*height*base

A(Triangle) = 0.5 X Base X perpendicular height Substituting A = 0.5 X 7 X 6 => A = 0.5 X 42 => A = 21 sq. ins.

A triangle twice as high as a parallelogram with the same base has the same area.

96 square inches.

Slope = Height/Base = 40/60 = 2/3

Related questions

a*b=(h*B)/2, a&b being the sides of the rectangle, h the height of the triangle and B the base: 8*5=(2B)/2 40=B

The height has not been given but the area of the triangle is: 0.5*height*base

A(Triangle) = 0.5 X Base X perpendicular height Substituting A = 0.5 X 7 X 6 => A = 0.5 X 42 => A = 21 sq. ins.

A triangle twice as high as a parallelogram with the same base has the same area.

assuming its an isosceles triangle, then its 16 cm high

The formula is bXh or base times height. if for instance you had a quadrilateral with a base that is 2 inches in length and is 3 inches high its area would be 6in2 .

Yes. If you drew them one on top of another, the parallelogram would be a "squashed" one that was not very high when compared to the height of the triangle. But it is eminently possible to have the two figures contain the same area and have the same base.

96 square inches.

Volume = cross-sectional area x length, so 6 x 12=72

It depends on whether the figure is a triangle, a rectangle, or some other shape.

its when your bumhole is shaped like a triangle

A triangle.