The height has not been given but the area of the triangle is: 0.5*height*base
A triangle twice as high as a parallelogram with the same base has the same area.
To find the base of a triangle given its height and area, you can use the formula for the area of a triangle: Area = (1/2) × base × height. Rearranging the formula to solve for the base gives you base = (2 × Area) / height. Plugging in the values, base = (2 × 63.9) / 14.2, which calculates to approximately 9.0 inches.
To find the area of a triangle that is 7 inches wide and 7 inches high, we use the formula for the area of a triangle: ( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} ). Thus, the area is ( \frac{1}{2} \times 7 , \text{in} \times 7 , \text{in} = 24.5 , \text{in}^2 ). However, since the triangle is larger than the square (5 in by 5 in), it cannot fit inside the square. Therefore, the relevant area within the square would need to be calculated based on the triangle's dimensions fitting within the square's boundaries.
No. When we say triangles are similar we mean that they are the same shape. So a triangle could have the same shape but be double the size. It would then have an area 4 times the original triangle.Example: a right angled triangle with sides 3, 4 and 5 cm would be similar to a right angled triangle with sides 6,8 and 10 cm. The area of the first triangle would be (3x4)/2=6sq cm, while the area of the latter would be (6x8)/2+24 sq cm.When triangles are identical they are called "congruent". They are the same shape and size and the same area.The formula to calculate the area of a triangle is half(basexheight) or bh/2. Triangles of the same area do not have to be similar. It is just necessary that the product of the base and the height are the same. So a triangle with a base of 4 and a height of 3cm would have the same area area as a triangle with a base of 1 and a height of 12cm.No. Long thin triangles can have the same area as short fat ones but they will not be similar just as two rectangles may have the same area but different proportions.Example:A rectangle 4 * 6 units has an area of 24 square units, so does a rectangle that is 2 * 12 units.Now the cut these rectangles in half, corner to diametrically opposite corner and you have triangles. The one 6 units long and 4 units high and the other 12 units long by 2 units. These have the same area (the both are 12 square units) but are not similar.
A(Triangle) = 0.5 X Base X perpendicular height Substituting A = 0.5 X 7 X 6 => A = 0.5 X 42 => A = 21 sq. ins.
A triangle twice as high as a parallelogram with the same base has the same area.
To find the base of a triangle given its height and area, you can use the formula for the area of a triangle: Area = (1/2) × base × height. Rearranging the formula to solve for the base gives you base = (2 × Area) / height. Plugging in the values, base = (2 × 63.9) / 14.2, which calculates to approximately 9.0 inches.
assuming its an isosceles triangle, then its 16 cm high
Yes. If you drew them one on top of another, the parallelogram would be a "squashed" one that was not very high when compared to the height of the triangle. But it is eminently possible to have the two figures contain the same area and have the same base.
It depends on whether the figure is a triangle, a rectangle, or some other shape.
a*b=(h*B)/2, a&b being the sides of the rectangle, h the height of the triangle and B the base: 8*5=(2B)/2 40=B
A triangle.
To find the area of a triangle that is 7 inches wide and 7 inches high, we use the formula for the area of a triangle: ( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} ). Thus, the area is ( \frac{1}{2} \times 7 , \text{in} \times 7 , \text{in} = 24.5 , \text{in}^2 ). However, since the triangle is larger than the square (5 in by 5 in), it cannot fit inside the square. Therefore, the relevant area within the square would need to be calculated based on the triangle's dimensions fitting within the square's boundaries.
If the sides of the triangle are equal it is an isosccees triangle. Therefore the altitude (height) of the triangle divides the base into two equal parts. This resu;ts in two equal right angle triangles. The length of either equal side is the hypotenuse of a right triangle and its length follows directly from application of the Pythagorean thereom. length squared = base/2 sqiared + height squared or c2=a2+b2. c2=(12/2)2+82 =36+64=100 so c=10
No. When we say triangles are similar we mean that they are the same shape. So a triangle could have the same shape but be double the size. It would then have an area 4 times the original triangle.Example: a right angled triangle with sides 3, 4 and 5 cm would be similar to a right angled triangle with sides 6,8 and 10 cm. The area of the first triangle would be (3x4)/2=6sq cm, while the area of the latter would be (6x8)/2+24 sq cm.When triangles are identical they are called "congruent". They are the same shape and size and the same area.The formula to calculate the area of a triangle is half(basexheight) or bh/2. Triangles of the same area do not have to be similar. It is just necessary that the product of the base and the height are the same. So a triangle with a base of 4 and a height of 3cm would have the same area area as a triangle with a base of 1 and a height of 12cm.No. Long thin triangles can have the same area as short fat ones but they will not be similar just as two rectangles may have the same area but different proportions.Example:A rectangle 4 * 6 units has an area of 24 square units, so does a rectangle that is 2 * 12 units.Now the cut these rectangles in half, corner to diametrically opposite corner and you have triangles. The one 6 units long and 4 units high and the other 12 units long by 2 units. These have the same area (the both are 12 square units) but are not similar.
A(Triangle) = 0.5 X Base X perpendicular height Substituting A = 0.5 X 7 X 6 => A = 0.5 X 42 => A = 21 sq. ins.
Divide polygon into rectangles, then use area formula for rectangle: Area = (high a + high b) / 2 x length c If polygon contains triangle, then triangle can be considered as rectangle with one of its side length is close to zero.