The answer will depend on the units used for the area: whether the area is 60 square feet, 60 square yards or 60 square miles, for example, DOES make a difference.
If you know the total area and the height are known, you can find the base. Area=(1/2)(base)(height), so if you know the height and area you can solve for the base. So now, Base=Area/(1/2)(height)
Area = Base * Height so Base = Area/Height
You can find the height of a parallelogram given the area and base measures by working backwards from the area formula. The area of a parallelogram is found with the formula: Area = Base * Height To solve this equation for Height, we divide both sides by the base. Area / Base = (Base * Height) / Base Simplify: Area / Base = Height
Total surface area = 2*pi*r*(r + h) where r is the base radius and h the height.
Area = 0.5*Base*Height
If you know the total area and the height are known, you can find the base. Area=(1/2)(base)(height), so if you know the height and area you can solve for the base. So now, Base=Area/(1/2)(height)
Area = Base * Height so Base = Area/Height
You can find the height of a parallelogram given the area and base measures by working backwards from the area formula. The area of a parallelogram is found with the formula: Area = Base * Height To solve this equation for Height, we divide both sides by the base. Area / Base = (Base * Height) / Base Simplify: Area / Base = Height
Area of a triangle = base * height / 2 Therefore the base = Area * 2 / height
The relation between the height of a triangle, its base and its area is given by: Area = 0.5 * Base * Height Therefore, we have: Height = (2 * Area)/ Base.
3
Area = 1/2*Base*Height so Base = 2*Area/Height
Total surface area = 2*pi*r*(r + h) where r is the base radius and h the height.
first find the area of the base. then multiply it by the height and divide it by three.
Area = 0.5*Base*Height
If the shape in question is a triangle, then Area = 0.5 * Base * Height So Height = 2 * Area / Base
Of a square? (area/height=base) Of a triangle? ({area/height}/2=base) Or of some other shape?