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The perimeter of a rectangle is 32 inches Its length is 10 inches What is its width?
32 = L + W + L + W 32 = 10 + W + 10 + W 12 = W + W 6 = W
The perimeter of an rectangle is 64cm the length is 8cm more than twice the width Find the dimensions?
That means that 2(L+W)=64 => L+W =32. We can also form the equation L = 8+2w. Plugging this expression into the first equation for L we get 8+2w+W = 32. Simplifying we get 3w+8 = 32 => 3w=24 => w=8. Using the fact that L+W=32 and our value for w we get L+8=32 => L=24. Therefore the dimensions are a length of 24cm and a width of 8cm.
What is a flow chart to find the area and circumference of rectangle?
start real length L and width w calculate the area A= Lw calculate the circumference C=2(L+w) Display A and C End
If a carpet has an area of 48 square meters and the perimeter is 32 square meters what is the length and width?
Length (L) x Width (W) = Area 2*L+2*W = Perimeter 48/W=L (solved for L) 2*48/W+2*W=32 (inserted L into perimeter equation) 48+W^2=16*W (quadratic equation or factor) W=12 or 4 Therefore L=4 when W= 12 or L=12 when W=4 Length (L) x Width (W) = Area 2*L+2*W = Perimeter 48/W=L (solved for L) 2*48/W+2*W=32 (inserted L into perimeter equation) 48+W^2=16*W (quadratic equation or factor) W=12 or 4 Therefore L=4 when W= 12 or L=12 when W=4
How is area determined?
Its determined by the formula: l x w Ex: l=32 w=2 a= 64
Find the perimeter of a rectangle 12.5 cm long and 3.5 cm wide?
The perimeter of a rectangle is simply the sum of the length of all four sides. So, l + w + l + w, or 2(l + w).
Parallelogram is 4 cm and an area of 32 square cm?
The formula for finding the area of a parallelogram is A = L * W (L is length, and W is width. Using the same formula, set it up: A = L * W (then substitute with the known dimensions) 32 = L * 4 (then divide both sides by 4 to find l) 8 = L
How do you find the circumference of a rectangle?
The perimeter (P) of a rectangle is the sum of the length's of all four sides which can be simplified by using the length (l) and width (w) as follows: P = 2*w+2*l.
What is youth size 18 in girls pants?
Small 6-818" W - 28" L, Medium 10-1220" W - 29" L, Large 14-1622" W - 30" L , X-Large 18-2024" W - 31" L ,2X 22-2426" W - 32" L, 3X 26-2828" W - 33" L 4X30-3230" W - 34" L .this is all sizes and measurements
What are the dimensions of the largest rectangular pen that can be enclosed with 64 meters of fence?
To find the dimensions of the largest rectangular pen that can be enclosed with 64 meters of fence, we can use the formula for the perimeter of a rectangle, which is (P = 2(l + w)), where (l) is length and (w) is width. Setting the perimeter equal to 64 meters gives us (l + w = 32). To maximize the area (A = l \times w), we can express (w) as (w = 32 - l) and find the maximum area occurs when (l = w = 16). Therefore, the dimensions of the largest rectangular pen are 16 meters by 16 meters, making it a square.
What is the length and width of a rectangle with a perimeter of 32 feet and area of 48 feet squared?
12 and 4. Either one can be the length, the other is the width. To solve algebraically: 2L + 2W = 32 L x W = 48 substitute the L value for W (W = 16-L) L (16-L) = 48 -L2 +16L -48 = 0 L2 -16L + 48 = 0 (L-12)(L-4) = 0
What is the total area of a retangular prism that is 2 inches wide 9 inches tall and 16 inches long?
Area = 2*(W*H + H*L + L*W) = 2*(2*9 + 9*16 + 16*2) = 2*(18 + 144 + 32) = 2*194 = 388 sq inches.Area = 2*(W*H + H*L + L*W) = 2*(2*9 + 9*16 + 16*2) = 2*(18 + 144 + 32) = 2*194 = 388 sq inches.Area = 2*(W*H + H*L + L*W) = 2*(2*9 + 9*16 + 16*2) = 2*(18 + 144 + 32) = 2*194 = 388 sq inches.Area = 2*(W*H + H*L + L*W) = 2*(2*9 + 9*16 + 16*2) = 2*(18 + 144 + 32) = 2*194 = 388 sq inches.
