Q: What is the coefficients of 12a3 plus 16a plus 4?

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They are 3 and 4

-5 & 3

-4 + 2A = 12 - 15A + A-4 + 2A = 12 - 16A2A = 12 - 16A + 42A = 16 - 16AA = 8 - 8A

2w-6w+9 -4w+9 the coefficient of -4w is -4

The coefficients of the unknown variables are 3 and -4 respectively and the given quadratic expression can be factored as (3x-1)(x-1)

Related questions

(48a3+32a2+16a)/4a = 12a2+8a+4

4

It is: 19a+27b-9 simplified

1,4,6,4,1

They are 3 and 4

-5 & 3

Assuming that "terma coffients" stands for terms and coefficients, they areterms: 3d, d4 coefficients: 3, 4.

2, 4, 4.5 and 17

-4 + 2A = 12 - 15A + A-4 + 2A = 12 - 16A2A = 12 - 16A + 42A = 16 - 16AA = 8 - 8A

You need to combine the different parts that contain the variable "a". Just add the coefficients together algebraically.

2w-6w+9 -4w+9 the coefficient of -4w is -4

16A