In the expression (12a^3 + 16a + 4), the coefficients are the numerical factors that multiply each term. The coefficient of (a^3) is 12, the coefficient of (a) is 16, and the constant term (which can be considered as (a^0)) has a coefficient of 4. Therefore, the coefficients are 12, 16, and 4.
They are 3 and 4
-5 & 3
-4 + 2A = 12 - 15A + A-4 + 2A = 12 - 16A2A = 12 - 16A + 42A = 16 - 16AA = 8 - 8A
2w-6w+9 -4w+9 the coefficient of -4w is -4
To determine if ( 4(4a - 8) ) is equivalent to ( 6a ) and ( 8a - 8 ), we can simplify both expressions. First, simplify ( 4(4a - 8) ): [ 4(4a - 8) = 16a - 32 ] Now let's compare ( 16a - 32 ) with ( 6a ) and ( 8a - 8 ). Clearly, ( 16a - 32 ) is not equivalent to ( 6a ) or ( 8a - 8 ). Thus, ( 4(4a - 8) ) is not equivalent to either expression.
(48a3+32a2+16a)/4a = 12a2+8a+4
It is: 19a+27b-9 simplified
1,4,6,4,1
They are 3 and 4
The sum of the coefficients of the chemical equation SF4 + H2O + H2SO + HF is 1 + 2 + 1 + 1 = 5.
-5 & 3
Assuming that "terma coffients" stands for terms and coefficients, they areterms: 3d, d4 coefficients: 3, 4.
2, 4, 4.5 and 17
-4 + 2A = 12 - 15A + A-4 + 2A = 12 - 16A2A = 12 - 16A + 42A = 16 - 16AA = 8 - 8A
You need to combine the different parts that contain the variable "a". Just add the coefficients together algebraically.
2w-6w+9 -4w+9 the coefficient of -4w is -4
16A