21
To compare one third (1/3) and four sevenths (4/7), we can convert both fractions to a common denominator or convert them to decimals. One third is approximately 0.333, while four sevenths is approximately 0.571. Therefore, four sevenths is bigger than one third.
To find one third minus two sevenths, you first need a common denominator. The least common multiple of 3 and 7 is 21. Converting the fractions, one third becomes 7/21 and two sevenths becomes 6/21. Thus, 7/21 - 6/21 equals 1/21.
1/2 = 3/6 1/3 = 2/6 so your common denominator would be 6
1
22/21 = 1 1/21. The common denominator is 21, so 5/7 = 15/21, and 1/3 = 7/21. Add 15/21 + 7/21 = 22/21. Then change to mixed number.
1 1/2
To find the least common denominator of 1/3 and 1/4, we need to determine the smallest multiple that both denominators (3 and 4) have in common. The least common denominator is the least common multiple (LCM) of the denominators. The LCM of 3 and 4 is 12, so the least common denominator of 1/3 and 1/4 is 12.
It is 10/21.
The LCD of 1/3 and 1/9 is 9.
You can find this out in any of the following ways: 1. Find a common denominator (multiplying the two denominators is one way - it need not be the LEAST common denominator). Convert the fractions to this common denominator. Then you can compare. 2. Use a calculator to convert the fractions to decimal, then compare. To convert to decimal, just divide the top part of the fraction by the bottom part.
I got 39/56 you have to multiply each fraction by its denominator (4/7 x 8/8 and 1/8 x 7/7) so that way you get a common denominator. then when you multiply them which is (32/56 and 7/56) you add them ultimately getting the answer 39/56. You have to remember that when you add fractions you have to have a common denominator.
To find six sevenths times one third, you multiply the numerators and the denominators. So, ( \frac{6}{7} \times \frac{1}{3} = \frac{6 \times 1}{7 \times 3} = \frac{6}{21} ). This fraction can be simplified by dividing both the numerator and the denominator by 3, resulting in ( \frac{2}{7} ).