The factorization of 56 is 2 x 2 x 2 x 7. For it to be common, it would need to be compared to another factorization.
The prime factorization of 21 is 3 x 7 = 21The prime factorization of 56 is 2 x 2 x 2 x 7 = 56The GCF of 21 and 56 is 7.
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The prime factorization of 56 is:7 x 23 = 56
Prime factorization of 7 = 7 Prime factorization of 56 = 2*2*2*7 Common number(factor in factorization) or simply H.C.F.= 7 L.C.M. = H.C.F. * Product of other numbers = 7*2*2*2 = 56 In this case 7 is an exact divisor of 56, therefore L.C.M. = 56
To find the greatest common factor (GCF) of 56, 64, and 104, we first need to find the prime factorization of each number. The prime factorization of 56 is 2^3 * 7, the prime factorization of 64 is 2^6, and the prime factorization of 104 is 2^3 * 13. To find the GCF, we look for the highest power of common prime factors in all the numbers, which is 2^3. Therefore, the greatest common factor for 56, 64, and 104 is 8.
To find the greatest common factor (GCF) of 112, 56, and 85, we first need to find the prime factorization of each number. The prime factorization of 112 is 2^4 * 7, the prime factorization of 56 is 2^3 * 7, and the prime factorization of 85 is 5 * 17. To find the GCF, we identify the common prime factors and multiply them together. In this case, the GCF of 112, 56, and 85 is 7.
1Prime factorization of:56 = 2 * 2 * 2 * 775 = .................3 * 5 * 5=================GCF= 1 (56 and 75 don't have a common factor except 1)
56 = 23 × 7
56 is 8*7
The GCF of 14, 31, 39, and 56 is 1. One way to solve the problem is to notice that 31 is prime, and can't possibly be a factor of 14, which is smaller.If you prefer, you can write the prime factorization of each number in the set and find the GCF:The prime factorization of 14 is 2*7The prime factorization of 31 is 31 (1*31)The prime factorization of 39 is 3*39The prime factorization of 56 is 2*2*2*7So the GCF is 1.
Least Common Multiple (LCM) for 12 56 is 168
To find the least common multiple (LCM) of 2, 7, and 8, we first need to find the prime factorization of each number. The prime factorization of 2 is 2, 7 is already a prime number, and 8 is 2 x 2 x 2. Then, we take the highest power of each prime factor that appears in any of the numbers, which gives us 2^3 x 7 = 56. Therefore, the least common multiple of 2, 7, and 8 is 56.