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The largest integer is 211 - 1 which is 2048 - 1 = 2047

Q: What is the decimal equivalent of the largest binary integer that can be obtained with 11 bits?

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The one with the largest integer part (the part before the decimal point).

There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.

The largest unsigned integer is 26 - 1 = 63, giving the range 0 to 63; The largest signed integer is 25 - 1 = 31, giving the range -32 to 31.

To achieve the answer to what the decimal equivalent of the largest binary number with five places (or bits) is, work this equation: The formula is 2_ -1 where n is the number of bits. That will get you where you need to be.

Related questions

What is the decimal equivalent of the largest binary integer that can be obtained with (a) 11 bits and (b) 25 bits?

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(2^32) - 1

It is 216 - 1 = 65535.

It is Bin(1111111111111111) = Dec(65535).

65,535 in decimal = 1111111111111111 in binary.

The one with the largest integer part (the part before the decimal point).

There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.

The largest unsigned integer is 26 - 1 = 63, giving the range 0 to 63; The largest signed integer is 25 - 1 = 31, giving the range -32 to 31.

To achieve the answer to what the decimal equivalent of the largest binary number with five places (or bits) is, work this equation: The formula is 2_ -1 where n is the number of bits. That will get you where you need to be.

The largest integer equal to -100 is -100. The largest integer less than -100 is -101.

the largest integer of distinct power is 28