65,535 in decimal = 1111111111111111 in binary.
Normally a computer allocates a certain amount of memory space to store a number. This means that larger numbers are rounded and so not as accurate. By specifying that a number is a long integer, it is allocated twice the amount of storage space.For example, the largest integer that can be stored in 8-bits is 2^8 - 1 = 255.By doubling the storage to 16 bit, it becomes 65535.
4 is the largest integer that will divide evenly into both 16 and 36.
Every bit can be either 0 or 1. Therefore 4 bits can encode a maximum of 42 = 16 digits.
For an unsigned integer, that would be 216-1. For a signed integer in 2's complement notation, the largest number would be 215-1.
11b which is 1*2 + 1*1 = 3 would be for two bits. But a byte is 8 bits, so 2 bytes is 16 bits. The largest binary number is [2^16 - 1], which is 65535 (base ten)
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
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1111 1111 1111 1111 = 2^16 = 65536
Normally a computer allocates a certain amount of memory space to store a number. This means that larger numbers are rounded and so not as accurate. By specifying that a number is a long integer, it is allocated twice the amount of storage space.For example, the largest integer that can be stored in 8-bits is 2^8 - 1 = 255.By doubling the storage to 16 bit, it becomes 65535.
65,536
In computer programming, a variable can be (among other things) an integer or a long integer. An integer can be any whole number in the range of -32,768 to 32,767 A long integer can be any whole number in the range of -2,147,483,648 tp 2,147,483,647 I have never heard of an "integer" variable being called a "short integer" but it makes a kind of sense. Note: The size of integer types is platform-dependent, but usually: short: 16 bits int: 32 bits (16 in archaic systems: MSDOS OS Windows16) long: 32 bits (64 in unix64) long long: 64 bits
The largest binary number that can be expressed with 16 bits is 1111111111111111, which is equivalent to 65,535 in decimal. This number uses all 16 bits set to 1. In general, for an n-bit binary number, the maximum value is (2^n - 1). Thus, for 16 bits, it is (2^{16} - 1 = 65,535).
2^16-1= 65536
216 -1
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
65,535