It can be defined as the set of all integers that leave a remainder of 1 when divided by 2.
Any set of odd numbers, yes.
No. For example, 5 is an odd integer and 3 is an odd integer, yet 5/3 is neither an integer nor odd (as odd numbers are, by definition, integers).
There is no such pattern because there are no even odd numbers. Odd numbers, by definition, are odd and therefore, not even.
There are infinitely many odd numbers that are prime. Take any set of odd numbers greater than 1. Their product will be odd and, by definition, it will be composite. For example, 3*5*13 = 195.
1 is an odd number
The GCF of any set of odd numbers is odd because odd numbers don't have any even factors.
You can't. Adding any two odd numbers always gives an even number, which is not a member of the set of odd numbers.
even- equal odd- numbers like 3,5,7,9,11,etc.
Let + (addition) be a binary operation on the set of odd numbers S. The set S is closed under + if for all a, b ϵ S, we also have a + b ϵ S. Let 3, 5 ϵ the set of odd numbers 3 + 5 = 8 (8 is not an odd number) Since 3 + 5 = 8 is not an element of the set of the odd numbers, the set of the odd numbers is not closed under addition.
It is NOT a 'countable set'. It is an infinite set. 1, 3, 5, 7, 9, 11, ... you can count to infinity and keep going.
All even numbers have 2 as a factor - that is in their definition No odd numbers have 2 as a factor - that is in theirs. Trying to divide 2, or any multiple of it, into a number that by definition cannot be divided by 2, is a hopeless endeavour. There is no guarantee that you can divide an even number by an odd one, but it is not impossible.
the set of odd numbers is infinite