The drum should measure 23 inches diameter 36 inches height These are all external measurements.
Multiply 128 ounces by 55 gallons. There are 128 fluid ounces in a U.S. gallon. Therefore, 55 gallons would contain 6,400 fluid ounces.
To calculate the surface area of a 55-gallon drum, we first need to determine the dimensions of the drum. A standard 55-gallon drum typically has a diameter of 22.5 inches and a height of 33.5 inches. The surface area of a cylinder can be calculated using the formula 2πr² + 2πrh, where r is the radius and h is the height of the cylinder. Plugging in the values for the radius and height of the drum, we can calculate the surface area in square inches.
Unknown: 55 gal drum is a volume. This is the amount of volume this drum can hold. Gallon is a liquid measure, so, compounded with the fact that you don't know the mass or weight of the wheat, you don't have a dry measure. Are there air pockets? Is the wheat 100% dry? What is the mass of a given sample of wheat? After you answer these questions, just substitute for weight, and you will have your answer.
You can simplify 33 / 55 to 3 / 5 by dividing both by 11. The ratio is 3/5.
Height = 36 inches (3 feet) Diameter = 21 inches
Er...55 gallons?
55 gallons?
.2723122 to be exact
616 lbs
Dimensions are 970mm high by 580mm diameter
Volume = 55 gallons = 12,705 cubic inches = 7.3524 cubic feet (rounded)
The standard industrial oil (or barrel) drum has a capacity of 200-liters. In United States gallons (gal) one barrel holds 55-gal.
A 55-gallon drum of water weighs approximately 460 pounds.
A barrel is two 15.5 gal. kegs, a drum contains 55 gallons.
V=(πD2/4)h where D is the diameter of the 55 gallon drum and h is the height of the oil. Or if you prefer V=(2πr2h where r is the radius of the drum and h is as above.
The drum should measure 23 inches diameter 36 inches height These are all external measurements.