The drum should measure 23 inches diameter 36 inches height These are all external measurements.
Multiply 128 ounces by 55 gallons. There are 128 fluid ounces in a U.S. gallon. Therefore, 55 gallons would contain 6,400 fluid ounces.
To calculate the surface area of a 55-gallon drum, we first need to determine the dimensions of the drum. A standard 55-gallon drum typically has a diameter of 22.5 inches and a height of 33.5 inches. The surface area of a cylinder can be calculated using the formula 2πr² + 2πrh, where r is the radius and h is the height of the cylinder. Plugging in the values for the radius and height of the drum, we can calculate the surface area in square inches.
Unknown: 55 gal drum is a volume. This is the amount of volume this drum can hold. Gallon is a liquid measure, so, compounded with the fact that you don't know the mass or weight of the wheat, you don't have a dry measure. Are there air pockets? Is the wheat 100% dry? What is the mass of a given sample of wheat? After you answer these questions, just substitute for weight, and you will have your answer.
55 US fluid gallons of space is the same amount of space as 0.2082 cubic meters (rounded).It makes no difference how that volume of space is shaped, what kind of container it's in,or whether it's even IN a container.
Height = 36 inches (3 feet) Diameter = 21 inches
55 gallons?
Er...55 gallons?
616 lbs
.2723122 to be exact
Dimensions are 970mm high by 580mm diameter
Volume = 55 gallons = 12,705 cubic inches = 7.3524 cubic feet (rounded)
The standard industrial oil (or barrel) drum has a capacity of 200-liters. In United States gallons (gal) one barrel holds 55-gal.
A 55-gallon drum of water weighs approximately 460 pounds.
A barrel is two 15.5 gal. kegs, a drum contains 55 gallons.
V=(πD2/4)h where D is the diameter of the 55 gallon drum and h is the height of the oil. Or if you prefer V=(2πr2h where r is the radius of the drum and h is as above.
The drum should measure 23 inches diameter 36 inches height These are all external measurements.