The diameter of an octagon with sides of 11 feet can take any value between 0 feet and 44 feet.
11 ft diameter gives area = 95.03 sq feet (to 2 dp)
Assuming that the questions refers to the AREA of a CIRCLE with an 11 foot diameter, the answer is pi*(11/2)2 = 95.033 sq ft (to 3 dp).
V = 1,331 cubic feet.
The first ten polygons in order of names and sides are as follows:- Triangle has 3 sides Quadrilateral has 4 sides Pentagon has 5 sides Hexagon has 6 sides Heptagon has 7 sides Octagon has 8 sides Nonagon has 9 sides Decagon has 10 sides Undecagon has 11 sides Dodecagon has 12 sides
Area = pi*5.52 = 95.033 square feet to 3 d.p.
No
Its radius is 11 feet and so its diameter is 2*11 = 22 feet
35 feet.
The perimeter is the distance around your object. In this case you have a rectangle 10 feet by 11 feet. So two sides are 11 feet long, two sides are 10 feet long, the distance around it, is the sum of all those sides. 10 + 11 + 10 + 11 = distance around all four sides back to your starting point = 42 feet
389.40
It is: 3.5*pi which is about 11 feet
2 feet
Diameter=2xradius. Therefore radius=diameter/2. In this case the answer is 5.5 feet
11 ft diameter gives area = 95.03 sq feet (to 2 dp)
Circumference of a circle is pi multiplied by the diameter. If the diameter of the circle is 11 ft, the circumference is: 3.14 x 11 ft = 34.54 ft
A cylinder with a diameter of 1 foot and 3 feet high has a surface area of 11 square feet.
The volume in cubic feet of a cylinder with a diameter of 2 feet and a height of 6 feet is 18.85 cubic feet.