By suitable choice of its height, the diameter can be any value you like.
5000 ml There are 1000 milliliters in 1 liter. One milliliter is 0.001 liter
5000.Area of a square = 0.5*(diameter)^2
5
How much acid and chlorine should be added to a 5000 liter to make 5 ppm solution
It depends on the cable. 0 to 5000 volts the minimum bending radius is 6 x diameter of the cable. Above 5000 volts the minimum bending radius is 8 x the diameter of the cable.
The diameter of a nickel is 21.21 mm.
I liter = 1000 mL 5 liters = 5000mL
If the tank is cylindrical, then use the following formula: Area of a cylindrical shell: =2*pi*r*h =2*3.14*762/1000 *h m^2 =4.78536*h m^2 Weight of a cylindrical shell =Area*Thickness*Density =4.78536*h*0.003*8030 =115.279*h.......(1) Volume of a cylinder that you required=5000 liter=5 m^3 =pi*r^2*h =>5 m^3=3.14*[0.762]^2 *h =>h= 5 / [3.14*[0.762]^2] =>h=2.74 meter Weight of a cylindrical shell =115.279*h kg =115.279*2.74 kg =315.86446 kg ........(2) **Volume of a bottom circle =3.14*0.762^2*0.003 Volume of a bottom circle=0.00546966648 m^3 Weight of a bottom circle=0.00546966648*8030 =43.92 kg.....(3) Total weight=(2) +(3) Total weight=315.86446 kg +43.92 kg *Total weight of the cylindrical tank having 5000 liter capacity=359.78446 kg *Total weight of the cylindrical tank having 10000 liter capacity =315.86446*2 +43.92 kg =675.64892 kg
5 liters is equal to 5000 milliliters, as there are 1000 milliliters in 1 liter.
1 Liter has 1000 milliliters so 5 liters have 5000 ml.
5000 mlThere are 1000 milliliters in 1 liter. One milliliter is 0.001 liter.
1 liter (L) = 1000 milliliters (mL). Then 5 liters must be 5000 milliliters.