Are you sure you mean 3 metre and 6 metre lenses? They would both be incredibly long telephoto lenses (big, heavy, physically long), suitable for photographing wildlife from the other side of a National Park! You possibly mean 3millimetre (mm) and 6millimetre (mm) lenses. On compact digital cameras, a 3mm lens would be a very wide-angle lens and a 6mm lens would be a modest wide angle. On a DSLR you would be very unlikely to get a 3mm lens, a 6mm would be a very wide angle, most likely a fish-eye lens giving a round picture with great distortion. You need always to state the format a lens is used on to get a notion of whether it is wide-angle, normal or telephoto.
60m times pi so around 188.4m
You half the diameter, so the radius is basically 30m
I also do sprints for my track team. I think the best way to do this would be to double your time and add one second. the other way is just have someone time you in a 60m dash. shouldn't take longer than 9 seconds give or take ;)
In the UK its generally 60m but 30m within 3miles of an airport. You can ask for special dispensation by contacting the Civil aviation authority.
The tallest trees, the emergent layer, can be over 200ft (60m) tall. The canopy layer is about 30-40m (100-130 ft). The understorey layer is about 15-30m and the shrub layer is about 8m tall.
3600m2. this is 60m * 60m
Nope - 60m = 6000mm. 600mm is 60cm
1m= 100cm 60m= 100x60 60m=6000cm
Assuming the warehouse is a rectangle, the perimeter would be 100m + 60m + 100m + 60m = 320m.The area is 100m * 60 m = 6,000 sq m.
600cm is smaller than 60m because 1m is equal to 100cm, so 60m is equal to 6000cm.
There are infinitely many rectangles with an area of 30 m2Choose a width (greater than 0m and less than 30m) then the length will belength = 30 ÷ width.For example, if the width was 50 cm, the length would be 60m and the rectangle would have an area of 0.5m x 60m = 30 m2.If you want all the rectangles of area 30 m2 with whole number of meter sides then:1m by 30m2m by 15m3m by 10m5m by 6m
60m