25 m/s for 140 s
Distance = Rate X Time
so..........
due west displacement = 3500 meters ( call this a )
due south displacement = 1005 meters ( call this b )
you are looking for the hypotenuse of a triangle and your direction will be south westerly
a^2 + b^2 = c^2 ( you want c )
c = sqrt(a^2 + b^2)
= 3641.43 meters as magnitude
Direction of displacement from start point is arctan (1005 / 3500) = 16.021 degrees.
For interest the true compass direction from start point will be 270 - 16.021 = 253.98 degrees (true) on a chart. Compass degrees measure clockwise, starting at North is 0°
Rule: Magnitude of acceleration = Change of velocity / Time interval In linear motion, magnitude of acceleration is the measurement of change in speed in speed per unit time. For example: A car reaches a speed of 20 miles per second in 4 seconds, the magnitude of acceleration is 5 miles per second. a = 20 miles/second divided by 4 seconds = 5 miles per second. Acceleration is a vector, which means it has magnitude and direction. To describe accelerated motion completely, the direction also needs to be included. So it would be 5 miles per second in whatever direction it is going.
0.0002315 m/s OR 0.0008333 km/hour The velocity of an object is the rate of its change in position in a certain direction. Velocity is a vector quantity; this means that it has both a magnitude and direction. To find the average velocity of an object in motion, the following equation is used: average velocity= (total displacement)/ (total time elapsed) The SI units of velocity are "m/s" , but any distance unit over any time unit is also acceptable. Solving for the velocity asked for: First let's change hours to seconds: (12 hours ) x (6o minutes/hour )x (60 seconds/minute)= 43200 seconds Finding the velocity: average velocity= (displacement)/ (time)= 10m/ 43200 seconds= 0.000231481 m/s
2.2 x 109
2 meters every second. bit pointless
Distance is how far you go like the perimeter,or miles/kilometers.It is the amount of space or area you travel,or go.Example:You are standing in the middle of a field. Your house is 50 meters north of where you are.Draw a circle with radius 50 meters.Any place on that circle is a DISTANCE of 50 meters (magnitude= 50 meters, direction not important)If you decide to walk home, that is a DISPLACEMENT of 50 meters (Magnitude = 50 m, direction = NorthYou run in any direction and reach the circle in 50 seconds, that is a SPEED of 50 m/50s = 1 m/sYou run home and reach your house in 50 seconds, that is a VELOCITY of 50 m / 50 s = 1 m/s NorthYou start from a standing start. After 1 second you are running 0.75 m/s, after 2 s you are running 1.15 m/s your ACCELERATION is the change in VELOCITY divided by time.By Deena Dugdill12
-- Its magnitude is 1/2 of [ (the speed at 2 seconds) minus (the speed at zero) ]. -- Its direction is 1/2 of [ (the direction at 2 seconds) minus (the direction at zero) ].
Direction is to the right. Magnitude is 10 Newtons.
Rule: Magnitude of acceleration = Change of velocity / Time interval In linear motion, magnitude of acceleration is the measurement of change in speed in speed per unit time. For example: A car reaches a speed of 20 miles per second in 4 seconds, the magnitude of acceleration is 5 miles per second. a = 20 miles/second divided by 4 seconds = 5 miles per second. Acceleration is a vector, which means it has magnitude and direction. To describe accelerated motion completely, the direction also needs to be included. So it would be 5 miles per second in whatever direction it is going.
0.0002315 m/s OR 0.0008333 km/hour The velocity of an object is the rate of its change in position in a certain direction. Velocity is a vector quantity; this means that it has both a magnitude and direction. To find the average velocity of an object in motion, the following equation is used: average velocity= (total displacement)/ (total time elapsed) The SI units of velocity are "m/s" , but any distance unit over any time unit is also acceptable. Solving for the velocity asked for: First let's change hours to seconds: (12 hours ) x (6o minutes/hour )x (60 seconds/minute)= 43200 seconds Finding the velocity: average velocity= (displacement)/ (time)= 10m/ 43200 seconds= 0.000231481 m/s
Seconds and seconds have the same magnitude, so a value in seconds is already a value in seconds.
Speed is the magnitude component of velocity. Velocity is the displacement d during a time interval t . d = 2500 m and t = 8 seconds Solution : v = 2500/8 = 312.5 m/s
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Acceleration is a vector, meaning each acceleration has both magnitude and direction. The resultant of vectors is basically the net acceleration on the object expressed as a single vector. For example, if there are two vectors each with a magnitude of 2 meters/(seconds squared) acting on an object and these vectors were placed on the x and y axes then you could represent this system of 2 vectors 90 degrees apart each with a magnitude of two meters/(seconds squared) as one vector of 45 degrees with a magnitude of 2 times the square root of 2 meters/(seconds squared).
Acceleration is a vector, meaning each acceleration has both magnitude and direction. The resultant of vectors is basically the net acceleration on the object expressed as a single vector. For example, if there are two vectors each with a magnitude of 2 meters/(seconds squared) acting on an object and these vectors were placed on the x and y axes then you could represent this system of 2 vectors 90 degrees apart each with a magnitude of two meters/(seconds squared) as one vector of 45 degrees with a magnitude of 2 times the square root of 2 meters/(seconds squared).
Acceleration is a vector, meaning each acceleration has both magnitude and direction. The resultant of vectors is basically the net acceleration on the object expressed as a single vector. For example, if there are two vectors each with a magnitude of 2 meters/(seconds squared) acting on an object and these vectors were placed on the x and y axes then you could represent this system of 2 vectors 90 degrees apart each with a magnitude of two meters/(seconds squared) as one vector of 45 degrees with a magnitude of 2 times the square root of 2 meters/(seconds squared).
Velocity is derived by dividing displacement with time in seconds
78/60=1.3 1.3*5.1=6.63 78-6.63=71.37 The answer displacement after 5.1 seconds is 71.37 meters