0
Not quite sure of the given coordinates but in general the distance formula is:-
Square root of [(x1-x2)squared+(y1-y2)squared]
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What states that if ab 0 then a0 or b0?
the (zero-factor property)
Will the father have the same blood type as his son?
NO! each person has two factors determining their blood type - one from his mother, the other from his father. they can be either A, B or nothing(0). AA is A, A0 is A, BB is B, B0 is B, 00 is O and AB is AB. your mother gives one of her factors (alleles) to you, and the father the other one. each factor has a 50% chance of being transferred. so you can really have lots of possibilities. say your father is A0 and the mother B0, you can be either A0 (=A), AB (=AB), 00 (=O), or B0 (=B).
What is the example of determine?
Y= C + I C= a0 + a1Y + a2Y + u2 I= b0 + b1Yt-1 + b2rt-1 + u3 M= h0 = h1y + h2r + u4
What is example of determiners?
Y= C + I C= a0 + a1Y + a2Y + u2 I= b0 + b1Yt-1 + b2rt-1 + u3 M= h0 = h1y + h2r + u4
Resolution effect on nuclear magnetic resonance spectrum?
Resolution is affected by the strength of the B0 magnetic field. The j coupling (distance between lines in a quartet for instance) is a constant value in Hz. However the place that the lines appear is not. Increasing the magnet increases the distance between features while keeping the j coupling from overlapping (thus allowing independent, resolved peaks
What is an organized system of thoughts?
da b0$$
What is an organized system of thought called?
da b0$$
What causes b plus blood type?
if you receive B blood allele from both parents then the blood type is BB, which is B positive. B negative would be B0 where one parent donates B allele and the other 0. Its all the great wonders of genetics. You see, parents pass on traits from themselves to their children. In the case of blood type, each parent has 2 alleles, but they can only donate 1. So the child's blood type is then reflective of both parents. So if one parent was B0 and the other was AB. The first parent can donate B or 0, while the second can donate A or B. The child can have any combination of them but must receive one from each parent. So AB, BB, B0, and A0 are the possible combinations for these parents. Crazy stuff
Ben and Jerry Jerry start with the same number of trading cards. After Ben gives 12 of his cards to Jerry then has twice as many cards as Ben does. How many cards did Ben have at the start?
The easy way to answer this is to plug in numbers. Because you are given "12" and you are given "twice as many", the answer has to be a variable of 12 or 6. If you start plugging in numbers, you will find that 36 is the answer... Ben and Jerry start with 36 cards. Ben gives 12 of his cards to Jerry. Ben now has 24 and Jerry now has 48. 24 is one half of 48. For the actual math, you have to use variables. Please stick with it, this gets a little ugly if the child you are working with is as young as mine is. Ben at the start is equal to B0 Jerry at the start is equal to J0 At the start B0=J0 Now, Ben gives 12 of his cards to Jerry. The new value for Ben is B1 and B1 = B0-12. The new value for Jerry is J1 and J1 = J0+12. Also, we know that the new Jerry is twice the amount of the new Ben...J1 =B1 x 2. So, the below are known: 1: B0=J0 2: B1 = B0-12 3: J1 = J0+12 4: J1 = B1 x 2 So, using the last known, start to substitute the other values to get everything equal to the same variable. In this case, I'm going to solve it for B0. J1 = B1 x 2 J1 = (B0-12)x2 - Substitute B1 for B0-12, see line 2 J0+12=(B0-12)x2 - Substitute J1 for J0+12, see line 3 B0+12=(B0-12)x2 - Substitute J0 for B0, see line 1 1/2B0+6 = B0-12 - Divide the whole equation by 2 +6=B0-12-1/2B0 - Subtract 1/2B0 from both sides +18=B0-1/2B0 - Add 12 to both sides +18=1/2B0 - Simplify equation 36=B0 - Multiply both sides by 2 There is probably an easier way to do the above, but that's how I worked it out on paper.
The exponential expression b0 equals for any nonzero base b?
1
What is pseudo second order reaction?
The second order rate law -dA/dt = k [A] [B] for example if B is present in excess amount, the reaction rate reduces to pseudo first order, A0=0.01 M B0: 2 M AT= 0.0 M BT=1.99 M so the reaction rate depends on the concentration of A and the new reaction rate is pseudo first order; -dA/dt = kı [A] The third order rate law -dA/dt = k [A2] [B] If B is in excess amount, molarity of B0 is a very closer value to Bt ( for example ; B0= 2 M BT=1.99 M) the reaction becomes to be pseudo second order. -dA/dt = k [A2] Behzat BALCI enviromental enginneering of cukurova university
What does it mean when your eye gets watery?
uh.. it means malo is thinkinq about you .. =]- b0$sman
