Algebraic Properties of Real Numbers The basic algebraic properties of real numbers a,b and c are: Closure: a + b and ab are real numbers Commutative: a + b = b + a, ab = ba Associative: (a+b) + c = a + (b+c), (ab)c = a(bc) Distributive: (a+b)c = ac+bc Identity: a+0 = 0+a = a Inverse: a + (-a) = 0, a(1/a) = 1 Cancelation: If a+x=a+y, then x=y Zero-factor: a0 = 0a = 0 Negation: -(-a) = a, (-a)b= a(-b) = -(ab), (-a)(-b) = ab
Let the inputs be A2 A1 A0 & outputs be S5 S4 S3 S2 S1 S0. Now, make a truth table as follows A2 A1 A0 S5 S4 S3 S2 S1 S0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 1 0 0 0 0 1 0 0 and so on....... Finally we'll get S0 = A0 S1 = 0 S2 = A1 A2(bar) S3 = A0 [ A1 XOR A2] S4 = A2 [A1(bar) + A0 ] S5 = A1 A2
x-ab=0 x=ab
Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.
Yes
NO! each person has two factors determining their blood type - one from his mother, the other from his father. they can be either A, B or nothing(0). AA is A, A0 is A, BB is B, B0 is B, 00 is O and AB is AB. your mother gives one of her factors (alleles) to you, and the father the other one. each factor has a 50% chance of being transferred. so you can really have lots of possibilities. say your father is A0 and the mother B0, you can be either A0 (=A), AB (=AB), 00 (=O), or B0 (=B).
if you receive B blood allele from both parents then the blood type is BB, which is B positive. B negative would be B0 where one parent donates B allele and the other 0. Its all the great wonders of genetics. You see, parents pass on traits from themselves to their children. In the case of blood type, each parent has 2 alleles, but they can only donate 1. So the child's blood type is then reflective of both parents. So if one parent was B0 and the other was AB. The first parent can donate B or 0, while the second can donate A or B. The child can have any combination of them but must receive one from each parent. So AB, BB, B0, and A0 are the possible combinations for these parents. Crazy stuff
because type O (0 - zero) has no patterns, type A has A0 or AA pattern, type B has B0 or BB pattern and AB has AB pattern. patterns are combined, so A + B = AB, A + A = B, B+B = B and AB + 0 = AB (no pattern means nothing :)). It is the reason why blood type 0 is so rare, A0 + 00 will create A0, that means blood type A. Well, blood type 0 is not the most rare one... You know, when human is in uterus, the whole evolution is taking place. If something goes wrong, ppl can be born with animal blood as well, eg I have blood type C. EDIT ABO blood typing is simple. A and B are co-dominant genes, and O is recessive. So, A and B rule over O. Type A blood means that your alleles (only one can come from mother and one from father) are either AA (alleles as a pair are called genotype) or AO (type A because the A is dominant over the O) but to be type O, you need to O alleles, or OO genotype, each parent mathematically has to have at least 1 O allele. The parent with AB doesn't have the O gene.
Algebraic Properties of Real Numbers The basic algebraic properties of real numbers a,b and c are: Closure: a + b and ab are real numbers Commutative: a + b = b + a, ab = ba Associative: (a+b) + c = a + (b+c), (ab)c = a(bc) Distributive: (a+b)c = ac+bc Identity: a+0 = 0+a = a Inverse: a + (-a) = 0, a(1/a) = 1 Cancelation: If a+x=a+y, then x=y Zero-factor: a0 = 0a = 0 Negation: -(-a) = a, (-a)b= a(-b) = -(ab), (-a)(-b) = ab
Let the inputs be A2 A1 A0 & outputs be S5 S4 S3 S2 S1 S0. Now, make a truth table as follows A2 A1 A0 S5 S4 S3 S2 S1 S0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 1 0 1 0 0 0 0 1 0 0 and so on....... Finally we'll get S0 = A0 S1 = 0 S2 = A1 A2(bar) S3 = A0 [ A1 XOR A2] S4 = A2 [A1(bar) + A0 ] S5 = A1 A2
x-ab=0 x=ab
/* the sequence printed is Fibonacci's sequence, each element is calculated as a sum of two previous elements */#includeint main(){int i;int n;int a0=0;int a1=1;printf("How many elements do you want to print? ");scanf("%d",&n);printf("0 ");if (n > 0)printf("1 ");for (i = 2; i
x-ab=0 x=ab
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.Any number, raised to the power 0 is 1.This comes from the index law: ax* ay= ax+yLet y = 0 and you have ax* a0= ax+0But x+0 = x so the right hand side is ax.That means ax* a0= axSince this is true for all a, a0must be the multiplicative identity = 1.
Yes
It is not clear what the question requires. Yes, there are plenty of equations that have the same solution. For example, each and every equation of direct proportionality has the solution (0, 0). So what? every polynomial of the form y = anxn + an-1xn-1 + ... + a1x + a0 has the solution (0, a0). Again, so what?