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What is the distance between x-intercept and the z-intercept in the equation2x plus 9y-3z equals 18?
At the x-intercept, y' and 'z' are zero.
2x = 18
x = 9 . . . . . The intercept is (9, 0, 0)
At the z-intercept, 'x' and 'y' are zero.
-3z = 18
z = -6 . . . . . The intercept is (0, 0, -6)
The distance between the points is sqrt [ (9)2 + (0)2 + (-6)2 ] = sqrt(117) = 10.8167 (rounded)
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