for 3: count all number if divisable by 3 (123= 1+2+3= 6, 3+3=6)
for 5:end number is 5 or 0
the divisibility rule for 2 is: The number is even;the last digit ends with a 2,4,6,8,10, etc.The divisibility rule fir 3 is: The sum of the number is divisible by 3The divisibility rule for 4 is: The last two digits are divisible by 4The divisibility rule for 5 is: The number ends with a 5 or 0The divisibility rule for 6 is: The sum CAN be divisible by 2 and or 3The divisibility rule for 9 is: The sum of the number is divisible by 9The divisibility rule for 10 is : The number ends with a 0
If the rules for 2 and 3 work, the number is divisibale by 5.
2.50
It is 3 6 9
By using the divisibility rule for 3, we find that 117 is divisible by 3. That makes it composite.
the divisibility rule for 2 is: The number is even;the last digit ends with a 2,4,6,8,10, etc.The divisibility rule fir 3 is: The sum of the number is divisible by 3The divisibility rule for 4 is: The last two digits are divisible by 4The divisibility rule for 5 is: The number ends with a 5 or 0The divisibility rule for 6 is: The sum CAN be divisible by 2 and or 3The divisibility rule for 9 is: The sum of the number is divisible by 9The divisibility rule for 10 is : The number ends with a 0
If the rules for 2 and 3 work, the number is divisibale by 5.
2.50
The divisibility rule of 3 is that you add the digits together and then if the number you come up with is divisible by 3, then the number itself is divisible by 3. In this instance, 5 + 8 + 5 = 18/3 = 6, therefore, 585 is divisible by 3.
It is 3 6 9
there is a divisibility for 24 the rule is you can divide 24 as 6 and 4 i think
By using the divisibility rule for 3, we find that 117 is divisible by 3. That makes it composite.
A number is divisible by 15 if it is divisible by the prime factors of 15, that is, 5 and 3.
The rule for 1 and the rule for 3.
Every Number is a Multiple of 1 e.g., 5÷1=5, 3÷1=3, and 6÷1=6.
it is divisible by 3 and 9
3 - 31