480 is divisible by 9 but not evenly. When you divide 480 by 9 you get a quotient of 53 and a remainder of 3
There are two main methods:Euclid's methodChoose one of the numbers to be the dividend of a division and the other to be the divisor.Perform the divisionIgnore the quotient and keep the remainderIf the remainder is zero, the last divisor is the GCDReplace the dividend by the divisorReplace the divisor by the last remainderRepeat from step 2.It doesn't matter which number is the dividend and which is the divisor of the first division, but if the larger is chosen as the divisor, the first run through the steps above will swap the two over so that the larger becomes the dividend and the smaller the divisor - it is better to choose the larger as the dividend in the first place. Prime factorisationExpress the numbers in their prime factorisations in power format. Multiply the common primes to their lowest power together to get the GCD.The first is limited to two numbers, but the latter can be used to find the gcd of any number of numbers.Examples:GCD of 500 and 240:Euclid's method:500 ÷ 240 = 2 r 20 240 ÷ 20 = 6 r 0gcd = 20Prime factorisation:500 = 22 x 53 240 = 24 x 3 x 5gcd = 22 x 5 = 20
2173/53 = 41
53 divided by 7 is 7 with remainder 4
It is: 53/7 = 7 with a remainder of 4
Yes. The quotient is 53 .
53/8 = 48 remainder 5
Eight times with a remainder of five.
Not without remainder.
10 with a remainder of 3
53 goes into 83 once with remainder 30.
53 divided by 6 = 8 with a remainder of 5.