The divisor is 9.
quotient x divisor + remainder = dividend
⇒ quotient x divisor = dividend - remainder
⇒ divisor = (dividend - remainder) ÷ quotient
= (53 - 8) ÷ 5
= 45 ÷ 5
= 9
22
To determine how many times 53 can go into 376, we divide 376 by 53. The quotient is 7 with a remainder of 25. Therefore, 53 can go into 376 a total of 7 times with a remainder of 25.
There are two main methods:Euclid's methodChoose one of the numbers to be the dividend of a division and the other to be the divisor.Perform the divisionIgnore the quotient and keep the remainderIf the remainder is zero, the last divisor is the GCDReplace the dividend by the divisorReplace the divisor by the last remainderRepeat from step 2.It doesn't matter which number is the dividend and which is the divisor of the first division, but if the larger is chosen as the divisor, the first run through the steps above will swap the two over so that the larger becomes the dividend and the smaller the divisor - it is better to choose the larger as the dividend in the first place. Prime factorisationExpress the numbers in their prime factorisations in power format. Multiply the common primes to their lowest power together to get the GCD.The first is limited to two numbers, but the latter can be used to find the gcd of any number of numbers.Examples:GCD of 500 and 240:Euclid's method:500 ÷ 240 = 2 r 20 240 ÷ 20 = 6 r 0gcd = 20Prime factorisation:500 = 22 x 53 240 = 24 x 3 x 5gcd = 22 x 5 = 20
6.625
480 is divisible by 9 but not evenly. When you divide 480 by 9 you get a quotient of 53 and a remainder of 3
53
22
To determine how many times 53 can go into 376, we divide 376 by 53. The quotient is 7 with a remainder of 25. Therefore, 53 can go into 376 a total of 7 times with a remainder of 25.
Divide 54 by 2. Use the integer quotient obtained in this step as the dividend for the next step. Repeat the process until the quotient becomes 0. So we get answer 110110
There are two main methods:Euclid's methodChoose one of the numbers to be the dividend of a division and the other to be the divisor.Perform the divisionIgnore the quotient and keep the remainderIf the remainder is zero, the last divisor is the GCDReplace the dividend by the divisorReplace the divisor by the last remainderRepeat from step 2.It doesn't matter which number is the dividend and which is the divisor of the first division, but if the larger is chosen as the divisor, the first run through the steps above will swap the two over so that the larger becomes the dividend and the smaller the divisor - it is better to choose the larger as the dividend in the first place. Prime factorisationExpress the numbers in their prime factorisations in power format. Multiply the common primes to their lowest power together to get the GCD.The first is limited to two numbers, but the latter can be used to find the gcd of any number of numbers.Examples:GCD of 500 and 240:Euclid's method:500 ÷ 240 = 2 r 20 240 ÷ 20 = 6 r 0gcd = 20Prime factorisation:500 = 22 x 53 240 = 24 x 3 x 5gcd = 22 x 5 = 20
6.625
480 is divisible by 9 but not evenly. When you divide 480 by 9 you get a quotient of 53 and a remainder of 3
2173/53 = 41
When dividing 372 by a number, such as 7, the quotient is the result of the division without considering any remainder. In this case, 372 divided by 7 is 53, which is the quotient. The remainder is the amount left over after dividing as evenly as possible. In this case, the remainder would be 1, as 372 divided by 7 equals 53 with a remainder of 1.
53
53 divided by 7 is 7 with remainder 4
Well, honey, 8 can go into 53 a total of 6 times with a remainder of 5. So, if you're dividing 53 by 8, you'll get 6 with a little leftover. Math doesn't have to be complicated, just divide and conquer!