Remember, the geometry of a molecule has to do with how many electron pairs AND lone pairs there are around the CENTRAL atom. Basically, count up the lines and the pairs of dots.
Notice that 'Xe' has 8 electrons in its valence shell, and 'F' has only 7.
When we put 4 'F' atoms around 1 'Xe' atom, each Flourine atom is going to want to 'share' one of Xenon's electrons so that it can have 8 electrons.
Also remember that when an atom shares electrons, it shares in pairs. Each shared bond has 2 electrons.
Now count up the number of electron PAIRS around the CENTRAL atom. We have 4 bonds (one with each Fluorine atom), and 2 lone pairs of of electrons bringing our count up to 12 electrons around Xenon, or 6 pairs total. (This violates the 'Octet Rule', but it's ok in this situation)
Here is a list of geometries according to the number of Electron Domains:
2 'ED's (electron domains) = Linear shape
3 'ED's = Trigonal Planar
4 'ED's = Tetrahedral
5 'ED's = Trigonal Bi-pyramid
6 'ED's = Octahedral
The electron-domain geometry of XeF4 would be Octahedral.
Hope this helped!
XeF4
octaedrique
No it is not a tetrahedral!
One main characteristic of non-Euclidean geometry is hyperbolic geometry. The other is elliptic geometry. Non-Euclidean geometry is still closely related to Euclidean geometry.
molecular geometry is bent, electron geometry is tetrahedral
octaedrique
XeF4
Square Planar, Like XeF4
XeF4 is square planar
Yes, XeF4, or xenon tetrafluoride, has a Lewis structure.
XeF4+H2O->XeO3+HF+H2O
lCl3 = T- shaped XeF4 =Square planar SF4 =Seesaw H20 =Bent XeF2 =Linear
No. it does not.
No it is not a tetrahedral!
square planar
Yes
XeF4.