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Points: (0, 5) and (3, 0)

Midpoint: (1.5, 2.5)

Slope: -5/3

Perpendicular slope: 3/5

Perpendicular equation: y--5 = 3/5(x--3) => 5y = 3x-16

Distance is the square root of (1.5--3)^2+(2.5--5)^2 = 8.746 to three decimal places

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Q: What is the equation and its perpendicular distance from the point -3 -5 whose line meets the line of 0 5 to 3 0 at its midpoint on the Cartesian plane showing work?
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The mid-point is needed when the perpendicular bisector equation of a straight line is required. The distance formula is used when the length of a line is required.

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