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There is no such equation, what do you mean by "water from a distance".

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The volume of displaced water is equal to needed volume of the sample.

Measuring the volume of a baseball is a tough chemistry equation. To do so, you would have to measure the circumference to find the radius. Next, you would find the volume of a sphere. You would also have to know the density of water to complete the equation.

40205 cm is a measure of distance of length. A length has no volume and without a volume there can be no water. Therefore, the answer to the question is zero kg and 0 grams.

A gallon measures volume of water not distance.

The mass will depend upon the size of the water bottle. The density of water is 1, so you use the equation density=mass/volume.

Usually water displacement is used to determine the volume of an object. When the object is added to the water, the amount of displacement can be measured. I don't know if there is an equation to do this, but it most likely involves subtracting the final volume from the initial volume.~Jeff Johnsonwww.jeffjohnsonis.com

No. It will affect the distance the water rises, but not the volume of displacement.

Neither. -- Perimeter = the distance all the way around it. -- Area = how much of the floor it covers. -- Volume = how much water it can hold.

Depends on the substance. A gram of lead will have a lot less than a ml of volume, while a gram of oxygen will have a greater volume than 1 ml. Water is 1 ml per gram, but that changes with the temperature of the water. Warm water, and very cold water (<4o C) will have a somewhat greater volume than 1 ml per gram weight.

Water has a density of 1 g/mL. To convert volume and mass, you can use the equation d=m/v, or density = mass / volume. Water is a special case, since scientists designed the metric system to make this calculation easy, one mL of water has a mass of exactly one gram.

The basic way is you take the volume of the water before you put the object in the water, then you measure the volume of the water and object you put the in the water and then you subtract the volume of the water by itself from the volume of the water with the object in it. VO=Volume of object VW=Volume of water VWO=Volume of water and object Volume of object = Volume of water and object -(Minus)- Volume of water OR VO=VWO-VW

Firstly obtain a known volume of fresh water, say 100cm3. Then weigh the water and plug your values into the equation:- density = mass/volume ensure that mass is measured in g and volume in cm3 to obtain a density value in gcm-3 Water has a density of 1gcm-3

For converting a volume (cup) to a weight (grams) you must state what you are measuring. An American cup is 237 mL. If you are measuring water, a cup would be 237 grams of water.

because water atoms become power full due to heat energy and repulsive force increase so distance between atoms increase so at result volume of water increase

Specific gravity of an object is the density (= mass/volume) of the object compared with the same measure for water.

Here is the information you are given and a corresponding equation demonstrating the relationship between the given information and the unknown. Vtotal = Vwater + Vsand = 42cm3 Here is the given equation rearranged (by subtracting the volume of water from both sides) to target the unknown information (volume of sand). Vsand = Vtotal - Vwater Plugging in the given info to the equation yields your answer. Vsand = 42 - 20 Vsand = 22cm3

CO2 is the equation for carbon dioxide H2O is the equation for water

You have to use the density equation... D = M / V D= density M= mass V= volume You have to find the volume of your water. Since you know your density the only thing left to find out is the mass. Just solve for it by multiplying the volume times the density.

The volume of an object can be determined by the displacement of water. By dropping the object into a measuring container of water, where the volume of the water is known, the object's volume can then be calculated by subtracting the volume of the water by the volume of the water and object combined.

Volume = length * Width * Heigth

Octane and water do not react and so there is not an equation.

The volume does change if the initial values of the volume of sugar and water are looked at separately [(volume of sugar or volume of water becomes volume of sugar + volume of water when combined) as opposed to (volume of sugar + volume of water while separate becomes volume of sugar + volume of water when combined)]. If 2 grams sugar is poured into 2L water, the water will rise (a small bit, but it does rise). The sugar dissolves into the water in pieces too small to see with the naked eye.

The mass of 1 cc (cubic centimetre or cm3) of water is 1 gram. Strictly speaking, the equality of mass and volume measures applies for distilled water at 20 deg C at 1 atmosphere, but for all but the most extreme situations is valid.

According to the Gospel of John, converting water into wine was the first "sign" (miracle) that Jesus did.

The volume of the water displaced is equal to the volume of this object. Measuring the volume of the water displaced we find the volume of the object.