say g=10,mass =10 kg , force up =1000n
force down = mg = 10*10=100n
force up = 1000n, net force = 900 n up
force of 900 n acting on 10kg, using a=f/m , a=900/10, a = 90 m/s^2
you have to include a time in the data, lets say 10s
then s=(a*t^2)/2 , s=(90*100)/2 , s = 4 500 meters
power= force X distance / time where force = strength and distance/time = speed 100 kg lifted 0.6 m in 0.5 s = 120 kg X m/s =1,177 J/s or 1,177 W
Work is force times distance. A Force divided by Distance: looking at the units, Force = newtons = kg m / s^2 = mass x length / time^2 so ML/T^2 Distance = m = length so L Force/Distance = (ML/T^2)/L = ML/LT^2 = M/T^2 So the units of a force divided by distance are mass/ time^2 This would be the rate of change of mass change with respect to time.
In physics, work is defined by the product of force and perpendicular distance which it acts. The unit for work is the Joule(J) Work done = Force * Distance moved (Joules) (Newtons) (meters)
Impulse
Work = force * distance Work = 23N * 2.3 meters = 53 Joules of work is done ==================
The formula for finding work is: Work = force X distance. To find distance, you must divide both sides by force. After simplifying the equation, the new equation will read: distance = work divided by force
Force = Mass x Acceleration
The equation for ideal mechanical advantage is: Output force/input force, Or input distance/ output distance.
W= FxD is a balanced equation because Work is Force times distance.
Work = Force * work=Force x Distance
I believe that when you say 'lifted through', you mean lifted to a height of 10m. If so, the amount of work is such: Work= Force x Distance which have the units (Joules = Newtons x meters) When the object is lifted, it increases in its potential energy. The equation for this is: Potential energy = mass x gravitational force x height = 4.5 x 9.81 x 10 =441.45 Joules As 1 joule = 1 newton x meters and we have 441.45 Joules, 441.45 joules of works is done! :D
Force that did the work = (work done) divided by (distance the force acted through)
This is the equation for "work."
The force a lever can apply to a given point greatly depends on two distances:The distance from the pivot point to the object to be lifted and the distance from the pivot point to the point on the lever where force will be applied.To reduce the distance from the pivot-point to the point where Force is applied is to reduce the "force" of a lever.
Force x distance = 100 x 2 = 200 newton-meters = 200 joules.
Equation For Work:Work (J) = F x DF = Force (N), D = Distance (m)
Work = (force) x (distance) = (10) x (4) = 40 joules