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What is the equation of the straight line from the origin 0 0 to the mid-point of the line segment of 3 2 and 5 -1?
Wiki User
∙ 13y ago
y = 1/8x because it has no y intercept
Wiki User
∙ 13y ago
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What is the equation of the straight line from the origin to the midpoint of the line joining 3 2 and 5 -1?
It will have no y intercept and it is: y = 0.125x
What methods could you use to calculate the x-coordinate of the midpoint of a horizontal segment with the endpoints of (-60) and (60)?
If you mean endpoints of (-6, 0) and (6, 0) then the midpoint is at the origin of (0, 0)
What is an equation of the form ymx for the line that passes through the origin and has slope 2?
The straight line equation is: y = 2x
How do you form an equation for a line extending from the origin to the middle of the line segment joined to the points 3 2 and 5 -1?
First find the midpoint of (3, 2) and (5, -1) which is (4, 1/2) Then find the slope of (0, 0) and (4, 1/2) which is 1/8 Because there is no y intercept the equation is:- y = 1/8x
What are the characteristics of a line that has the equation y equals mx?
it's a straight line. Through the origin.
What is the equation of the straight line from the origin to the midpoint of the line joining 3 2 and 5 -1?
It will have no y intercept and it is: y = 0.125x
What is the equation that meets the coordinates of 3 2 and 5 -1 at their midpoint and stems from the origin?
The equation from the origin to the midpoint of the given points works out as y = 1/8x whereas 1/8 is the slope and there is no y intercept.
What is the equation of the straight line extending from the origin to the midpoint of the line joining 3 2 and 5 -1?
1st find the midpoint -- (4, 1/2) Now slope -- 1/2 divided by 4 = 1/8 y-intercept = 0 (origin) y = (1/8)x <--- answer
What is the length of the median that extends from the origin to the midpoint of the line segment of 12 0 and 0 -5?
Midpoint of line segment: (6, -2.5) Median line points: (6, -2.5) and (0, 0) Length of median line: 6.5
What methods could you use to calculate the x-coordinate of the midpoint of a horizontal segment with the endpoints of (-60) and (60)?
If you mean endpoints of (-6, 0) and (6, 0) then the midpoint is at the origin of (0, 0)
What methods could you use to calculate the x coordinate of the midpoint of a horizontal segment with the endpoints of -6 0 and 6 0?
You could use algebra (see below for how to do that), or you could graph the line and measure it.Using algebraThe x-coordinate of the midpoint of a line segment is the average of the x-coordinates of the end-points. 1/2(-6 + 6) = 0The y-coordinate of the midpoint of a line segment is the average of the y-coordinates of the end-points.1/2(0 + 0) = 0The midpoint of the given horizontal segment is the origin, (0, 0) .
If the midpoint of xy is located at the origin and one endpoint of this segment has coordinates of -8 10 what are the coordinates of the other endpoint?
The other end point is (8,-10).
How do you form an equation for a line extending from the origin to the middle of the line segment joined to the points 3 2 and 5 -1?
First find the midpoint of (3, 2) and (5, -1) which is (4, 1/2) Then find the slope of (0, 0) and (4, 1/2) which is 1/8 Because there is no y intercept the equation is:- y = 1/8x
What is an equation of the form ymx for the line that passes through the origin and has slope 2?
The straight line equation is: y = 2x
What are the characteristics of a line that has the equation y equals mx?
it's a straight line. Through the origin.
What is the equation and its distance from origin that meets the line joining the points 13 17 and 19 23 at its midpoint on the Cartesian plane showing work?
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
Enter an equation of the form y equals mx for the line that passes through the origin and has slope 2?
UndefinedImproved Answer:-The straight line equation is: y = 2x
