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Circle equation: x^2 +y^2 -8x -16y -209

Completing the squares: (x-4)^2 +(y-8)^2 = 289

Centre of circle: (4, 8)

Radius: 17

Slope of radius: 0

Tangent equation line: x = 21 passing through (21, 0)

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Q: What is the equation of the tangent line that touches the circle x squared plus y squared -8x -16y -209 equals 0 at the point of 21 and 8?
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