You first need to know how much the final contributes to the total grade. Let that be X%, so the final contributes X/100 to the semester grade, and your work, so far, contributes (1 - X/100).
If G is your average before the final, and F is the grade earned on the final, and T is the total grade:
T = G*(1-X/100) + F*(X/100). Rearranging, we get:
So if the final is worth 25%, {X/100 = 0.25}, and you have an 89, now, substituting in, you would need a 93 on the final to get a 90 for the class.
If the final is worth 25%, and you have an 95, now, you would need a 75 on the final to get a 90 for the class.
You will need to use your brain to figure that out. Different word problems need different equations.
X is an unknown quantity. You would need the rest of the equation to figure out the value of X.
The equation 25 times 753 equals to 18825. This is 5 grade math.
At least an a
But if you need the equation 1 ft = 12 inches 1 inch = 2.54 cm Hopefully you can figure it out from there!
my grade is a 92.3% and my final counts as only 10% so is the equation ... (92.3*.9)+(.1*D)=89.50 83.07+(.1*D)=89.50 -83.07 -83.07 __________________ (.1*D)=6.43 so now i divide by .1 so I'm just gonna move the . place over one so do i need a 64.3% on my final ????? KEY D = desired grade for final
To get a final grade of 72, you need a 72 on the exam. For a final grade of 75, you need an 72 on the exam. For a final grade of 80, you need a 99 on the exam. If you get 100 on the exam, your final grade will be a little over 80.
The answer depends on what aspect of travel you need to figure out.
If all your grades are weighted the same you add all of your grades together, then divide it by the number of grades you have for example: 97 82 35 67 86 43 (my grades not really) divided by 6 because that is how many grades i have = a 68% 68% is my final grade. If they have different weights then you need to multiply the grade by the % its worth.
if the 95 average is 75% of the grade then it stands for 71.25% of the final grade. Thus u need 18.75% more for 90% out of the remaining 25% which means u need atlst 75 marks out of 100 in your final paper! . karankilling16@yahoo.com
To figure a fraction, you need two parts to the equation. 6 liters by itself is a whole figure.
It depends on the weight given to the Final Exam. However, Here is an example where there are three components to the final grade, Attendance, Quizes and the Final Exam: {D - W(A) - X(Q)}/Y = Grade Needed on Final Where D = your desired final Grade. W= the weight given to Attendance (like 20%) and A=your current Attendance grade. X=the weight given to Quiz grades (like 30%) and Q=your current Quiz grade. Y=the weight given to the Final Exam (like 50%) W + X + Y must = 1 (100%) So, if you want to end up with a final grade of 90, and your Quiz scores average 80 but you have a 100 in Attendance, the formula is: {90 - .2(100) - .3(80)}/.5 = (90-20-24)/.5 = 46/.5 = 92 grade neede on Final If there are more than 3 components, the weight and current grade would go into the formula just like W(A) and X(Q), as a subtraction from D. Just make sure that all your weights always add to 1.
You need more information than is provided in the question.
You do not even need to get a 30% on the final. If you have a 100% in the class and get a 0% on the final, you willl still have an 85% in the class.
you just need to enclose your equation like this: \begin{figure*} \begin{equation} % % \end{equation} \end{figure*}
You will need to use your brain to figure that out. Different word problems need different equations.
To pass the course, you would need to achieve at least 50% overall. Since your current grade is 38% and the final is worth 30%, you would need to score 85% on the final exam to reach the 50% passing grade.