It depends on the weight given to the Final Exam. However, Here is an example where there are three components to the final grade, Attendance, Quizes and the Final Exam: {D - W(A) - X(Q)}/Y = Grade Needed on Final Where D = your desired final Grade. W= the weight given to Attendance (like 20%) and A=your current Attendance grade. X=the weight given to Quiz grades (like 30%) and Q=your current Quiz grade. Y=the weight given to the Final Exam (like 50%) W + X + Y must = 1 (100%) So, if you want to end up with a final grade of 90, and your Quiz scores average 80 but you have a 100 in Attendance, the formula is: {90 - .2(100) - .3(80)}/.5 = (90-20-24)/.5 = 46/.5 = 92 grade neede on Final If there are more than 3 components, the weight and current grade would go into the formula just like W(A) and X(Q), as a subtraction from D. Just make sure that all your weights always add to 1.
my grade is a 92.3% and my final counts as only 10% so is the equation ... (92.3*.9)+(.1*D)=89.50 83.07+(.1*D)=89.50 -83.07 -83.07 __________________ (.1*D)=6.43 so now i divide by .1 so I'm just gonna move the . place over one so do i need a 64.3% on my final ????? KEY D = desired grade for final
In most grading systems, your final grade is the average of your semester/marking period grades. Your mid-term and final exams might be separate and worth a percentage of your final grade. For example, in a high school divided into four marking periods, each marking period might be worth 20% of your final grade, and the mid-term/final exam might be worth 10% each of your final grade. Bottom line is that it depends on your individual school or college course. Each one may have a slightly different way of calculating your final grade, and you should contact them for specifics.
It depends on the equation.
You need more than one tangent to find the equation of a parabola.
Find values for the variable that satisfy the equation, that is if you replace those values for the variable into the original equation, the equation becomes a true statement.
my grade is a 92.3% and my final counts as only 10% so is the equation ... (92.3*.9)+(.1*D)=89.50 83.07+(.1*D)=89.50 -83.07 -83.07 __________________ (.1*D)=6.43 so now i divide by .1 so I'm just gonna move the . place over one so do i need a 64.3% on my final ????? KEY D = desired grade for final
In most grading systems, your final grade is the average of your semester/marking period grades. Your mid-term and final exams might be separate and worth a percentage of your final grade. For example, in a high school divided into four marking periods, each marking period might be worth 20% of your final grade, and the mid-term/final exam might be worth 10% each of your final grade. Bottom line is that it depends on your individual school or college course. Each one may have a slightly different way of calculating your final grade, and you should contact them for specifics.
In the equation m = k + 3, m is the:
First you must collect all the papers that were graded. Then you must add up all your grades. After you divide your answer by the number of graded papers you have. This process is called finding the mean or the average.
It is always easier to use an equation to find points since all you would have to do is substitute values into the equation to find the final unknown value that will tell the point. To get the equation, however, you would usually need to have some points at the start to help derive the equation in the end.
Average acceleration = final velocity - initial velocity/ final time - initial timeOr for short:Aave=Vf-Vi/Tf-TiHope that helps :)
You find the equation of a graph by finding an equation with a graph.
Use the equation a=(v-u)/t, whereby v stands for final velocity, u for initial velocity and t for time.
Okay here is what you want to do. You rearrange your equation of V1=a/d so that it looks like this --> v2= dxa and that is how you get your answer
If you take initial velocity(Vi) to be zero and the final velocity (Vo) to be a known. Puting the knowns into a triganonomical equation and solving for the value of D would give an answer
Write an algorithm to find the root of quadratic equation
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.