(3y - 5)(y + 5)
10y2 - 15y2 = -5y2
To express (15y + 40) in factored form, first, identify the greatest common factor (GCF) of the terms, which is 5. Factoring out the GCF, we get (5(3y + 8)). Thus, the factored form of (15y + 40) is (5(3y + 8)).
15y^8 - 7y^3 = y^3(15y^5 - 7)
No.
15y+14=2(5y+6) 15y+14=10y+12 15y+14-14=10y+12-14 15y=10y-2 15y-10y=10y-2-10y 5y=-2 y=-2/5
10y2 - 15y2 = -5y2
x2 + 8xy + 15y2 = (x + 3y) (x + 5y)
5
15y-15=0,y=1
(2x + 3y)(2x + 5y)
5(x + 2 + 3y)
3y plus 6x = 2
15y^8 - 7y^3 = y^3(15y^5 - 7)
65
No.
15y+14=2(5y+6) 15y+14=10y+12 15y+14-14=10y+12-14 15y=10y-2 15y-10y=10y-2-10y 5y=-2 y=-2/5
3xy-4x + 15y-20 Sol: As there are no number are same. So -4x-3xy +15y-20 -------------------- -4x-3xy+15y-20