15y+14=2(5y+6) 15y+14=10y+12 15y+14-14=10y+12-14 15y=10y-2 15y-10y=10y-2-10y 5y=-2 y=-2/5
10y=15y=1.5
(3y - 5)(y + 5)
15y^8 - 7y^3 = y^3(15y^5 - 7)
That would depend on the plus or minus values of 7x and 10y of which none have been given.
15y+14=2(5y+6) 15y+14=10y+12 15y+14-14=10y+12-14 15y=10y-2 15y-10y=10y-2-10y 5y=-2 y=-2/5
10y=15y=1.5
(3y - 5)(y + 5)
(y - 8)(y - 2)
15y^8 - 7y^3 = y^3(15y^5 - 7)
That would depend on the plus or minus values of 7x and 10y of which none have been given.
15y-15=0,y=1
3x squared minus 25x minus 28
2x squared minus 4
No, unless "a" happens to be equal to 0, or to 1.
x = ? 42 = x squared minus x
-22 - -22