(38,1)(19,2)
The factor pairs for 38 are (1, 19) and (2, 38).
(38,1)(19,2)
1 and 38, 2 and 19
1 and 38 2 and 19
38 = 1*38, 2*19
You're looking for factors of 38 that have a difference of 17. Luckily, 38 only has two factor pairs. It's not 38 and 1. (y - 2)(y + 19)
38 = 1*38, 2*1948 = 1*48, 2*24, 3*16, 4*12, 6*8
86
The following are the factor pairs of 950 factor pair = 950,1 factor pair = 475,2 factor pair = 190,5 factor pair = 95,10 factor pair = 50,19 factor pair = 38,25
Yes. Factor pairs are always repeated across pairs since factor pairs are certain kinds of pairs.
The factor pairs of 80 are (80,1)(40,2)(20,4)(16,5)(10,8) None of them add up to 38. If that was -80, you could use 40 and -2.
No, the number 38 is not a factor of 100.