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What is the first quartile of this data set 6 47 49 15 43 41 7 36?
Wiki User
∙ 6y ago
The first quartile is the value such that a quarter of the data are smaller than that value and three quarters are larger. Since there are 8 observations, the quartile will be between the second and the third smallest values. Therefore, Q1 = (7+15)/2 = 11
Wiki User
∙ 6y ago
Wiki User
∙ 9y agoThe first quartile is the value such that a quarter of the data are smaller than that value and three quarters are larger. Since there are 8 observations, the quartile will be between the second and the third smallest values. Therefore, Q1 = (7+15)/2 = 11.
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How do you calculate the third quartile for a mean of 110 and a standard deviation of 15?
If this is the only information you have, the answer would be somewhere around 125. Usually, you would find the third quartile by first finding the median. Then find the median of all of the numbers between the median and the largest number, which is the third quartile.
What is the mean deviation of the set of data 13 15 9 35 28 8?
9
What is the mean of the following set of data 8 9 15 6 7 2 1 and 0?
6.
What is the mode of this data set 8 11 20 10 2 17 15 5 16 15 25 6?
The mode is 15 because it occurs most often.
What is a set of data in which the mean is 15 the median is 15 and the mode is 13 and 15?
Remember what each of these terms represent. Mean = Mathematical Average Median = Middle value (exactly half of values are above and below) Mode = Most frequent value There are multiple possible answers, however here is one: 13, 13, 15, 15, 19 The mean is: (13 + 13 + 15 + 15 + 19)/5 = 75/5 = 15 The middle value (the median) is 15. Another way to say this is that, if we were to list all the values as shown above there are two before 15 and two after 15; therefore the median is 15. In this data set the value 13 occurs twice, 15 occurs twice, and 19 occurs once. Both 13 and 15 occur the most frequently therefore they are both the mode.
What is the first quartile of the following data set 12 33 15 22 29 11 17 19 16 24 38?
15
What is the first quartile of the following data set 12 33 15 22 29 11 17 19 10 24 38?
12
How do you find the quartiles of a data set?
First arrange the data set in ascending order. Suppose the data set consists of n observations. the index for the lower quartile is (n + 1)/4 and the index for the upper quartile is 3*(n + 1)/4. Find the values that correspond to the number in these positions in the ordered list. For example, if n = 15, then lower index = 4 and upper index = 12. So the lower quartile is the fourth number and the upper quartile is the twelfth. If n is large, you may skip the +1 and just look at n/4 and 3n/4. Often the indices are not integers. Then, if you are a beginner (nd the fact that you asked this question suggests that you are), find the nearest whole numbers for the two indices. Otherwise you need to interpolate and that is a whole new ball game!
What is the five number summary of a set of numbers?
The five number summary consists of the Minimum, the Lower Quartile, the Median, the Upper Quartile, and the Maximum.For Example, if you have a number set like this:2, 3, 5, 7, 9, 12, 15, 15, 18, 19, 21,Minimum: 2Q1: 5Median: 12Q3: 18Maximum: 21
What is the interquartile range of 54 and 65 and 66 and 68 and 73 and 75 and 75 and 78 and 82 and 82 and 87 and 97?
Since the set of data is arranged in numerical order, first we need to find the median (also called the second quartile), which separates the data into two equal groups, in our case there are 6 numbers in each group.54 65 66 68 73 75 | 75 78 82 82 87 97The first quartile (also called the lower quartile) is the middle value of numbers that are below the median, in our case is 67.54 65 66 | 68 73 75 | 75 78 82 82 87 97The third quartile (also called the upper quartile) is the middle value of numbers that are above the median, in our case is 82.54 65 66 | 68 73 75 | 75 78 82 | 82 87 97The interquartile range is the difference between the first and third quartiles, which is 15, (82 - 67).
How do you calculate the third quartile for a mean of 110 and a standard deviation of 15?
If this is the only information you have, the answer would be somewhere around 125. Usually, you would find the third quartile by first finding the median. Then find the median of all of the numbers between the median and the largest number, which is the third quartile.
What is the the 3rd quartile of a sample group of 15 20 25 27 28 28 28 30 34?
28 is the 3rd quartile.
Which set of data has a range of 15?
The one where the highest and lowest members differ by 15.
What could a data set with a mode of 11 and a median of 15 be?
16,11,18,11,15,17,11
What is the range of the data set shown 14 15 18 20 25?
11
How Can You Create A Data set With an Median and mean?
a data set in this case can be any collection of numbers you choose. Say we define Set A = {1,2,3,4,5} The Median for Set A is 3. The mean is the sum of the numbers divided by 5 in this case. 15/5 = 3 is the mean of Set A.
How do you find an interval on a graph?
to find an interval you have to subtract the first two number from each other for example 5 10 15 20 the interval for this set of data is 5
