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Q: What is the mean of the following set of data 8 9 15 6 7 2 1 and 0?
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What is the mean of the following data values 22 37 49 15 92?

39


How Can You Create A Data set With an Median and mean?

a data set in this case can be any collection of numbers you choose. Say we define Set A = {1,2,3,4,5} The Median for Set A is 3. The mean is the sum of the numbers divided by 5 in this case. 15/5 = 3 is the mean of Set A.


When the lower 50 percent of data has greater range the mean will be what to the median?

Whatever you like. The median value for each of the following three sets is 10. For the set {1, 9, 11, 12}. the mean is 8.25, smaller than the median. For the set {1, 9, 15, 15}. the mean is 10, the same as the median. For the set {1, 9, 15, 16}. the mean is 10.25, larger than the median.


A data set has 9 values The mean of the set is 5 When a tenth value is added the mean becomes 6 What is the tenth value?

15


What is the first quartile of the following data set 12 33 15 22 29 11 17 19 16 24 38?

15


What is the mean deviation of the set of data 13 15 9 35 28 8?

9


What is the mean of the following data 22 37 15 72?

a. 39 b. 47 c. 49 d. 37


What is the first quartile of the following data set 12 33 15 22 29 11 17 19 10 24 38?

12


What is the mean of the following set of numbers 38 46 15 27 36?

38+46+15+27+36 = 162 and 162/5 = 32.4 which is the mean average


Which set of data has a range of 15?

The one where the highest and lowest members differ by 15.


How do you find the median with an even data set?

The median is the mean of the middle two. For example, find the median of the set {1, 3, 4, 6, 9, 10, 15, 20}. There are 8 items in the data set, so the median is the mean of the middle two. The middle two are the 4th and 5th data items: 6 & 9 median = mean of 6 & 9 = (6 + 9)/2 = 7.5


A large set of data has a mean of 100 and standard deviation of 15Five are addedto each score in data what is the new mean and standard deviation?

The mean will move up by 5 also as the whole data set has shifted up by 5, hence the mean is 105. The spread of the data has not changed, its just been "lifted up and moved along 5" and so the standard deviation is the same, i.e. 15 Hope this helps