Since all decent programming languages have the multiplication operator, you simply multiply them. If you want to go into a bit more detail, it would be a bit like this:
Ask user for number "a"
Ask user for number "b"
Calculate result = a * b
Show result
(End)
Use the appropriate flow chart symbols for input, etc.
(Label1)Start Program:
(Label2)Prompt for First Number:
Enter First Number, Enter "End" to Exit Program
Store First Number after validity checking, If validity fails go to Label2
(Label3)Prompt for Second Number:
Enter Second Number, Enter "End" to Exit Program
Store Second Number after validity checking, If validity fails go to Label3
Do the multiplication operation, store product if necessary and display result
Go to Label 2
(Label4)Exit Program
int x; //first number int y; //second number int z = x*y;
fsck
create a program that iterates until it finds a perfect number, then store that perfect number into an array. Continue iterating until you find three more. Then, you have an array of four perfect numbers.
write a c program that takes a binary file as input and finds error check using different mechanisms.
I think it becomes a product that everybody can use
int x; //first number int y; //second number int z = x*y;
it will be destroyed.
fsck
Impossible sorry. :(
create a program that iterates until it finds a perfect number, then store that perfect number into an array. Continue iterating until you find three more. Then, you have an array of four perfect numbers.
The Jack Benny Program - 1950 Jack Finds a Double 15-23 was released on: USA: 12 March 1965
www.whitepages.com finds peoples address and phone numbers
write a c program that takes a binary file as input and finds error check using different mechanisms.
I think it becomes a product that everybody can use
A "web crawler", A "search engine", A "web browser.
Driver Manager is a program that scans and finds out what is missing in your computer such as a missing driver.
Try thisinput "z =?";x,yprint "z=";x;"+";y;"i"input "w =?";u,vprint "w=";u;"+";v;"i"print "z+w = ";x+u;"+";y+v;"i"print "z*w = ";x*u-y*v;"+";x*v+y*u;"i"example output:z=? 1,2w=? 2,3z+w = 3+5iz*w = -4+7iNote that it is possible to input negative imaginary parts. To display the sum and product correctly in that case, you need to make an intermediate step in the program which assigns the imaginary part to a separate variable, decide whether or not the imaginary part is negative, and then print a "+" if it is positive or no sign when it is negative (printing a negative number will automatically print the negative sign).Of course, you need to modify the program to your computer language.