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x2 + y2 =

x2 + y2 = 5

x2 + y2 = 10

x2 + y2 = 25

Q: What is the following equation if a circle whose center is at the origin and whose radius is SQ RT of 5?

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x² + y² = 81.

x² + y² = 4.

x2 + y2 = 16

x2 + y2 = 81

x2 + y2 = 49

Related questions

The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100

9

x2 + y2 = 64

x² + y² = 81.

x² + y² = 4.

x2 + y2 = 16

x2 + y2 = 81

x2 + y2 = 49

x2 + y2 = r2, where r is the radius.

It is x2 + y2 = 4

A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1

x2 + y2 = 2