x2 + y2 = r2, where r is the radius.
x2 + y2 = 2
It is x2 + y2 = 4
x2 + y2 = 49
(x-0)² + (y-0)² = r²
x2 + y2 =x2 + y2 = 5x2 + y2 = 10x2 + y2 = 25
x2 + y2 = 2
It is x2 + y2 = 4
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
x2 + y2 = 49
(x-0)² + (y-0)² = r²
9
x2 + y2 =x2 + y2 = 5x2 + y2 = 10x2 + y2 = 25
-40
There are infinitely many points. One of these is (10, 0).
No. Every circle on the sphere whose center is also the center of the sphere is a great circle. If the circle's center is not also the center of the sphere, then the circle is a small circle.
The points that lie on a circle centered at the origin (0, 0) with a radius of 10 satisfy the equation (x^2 + y^2 = 10^2) or (x^2 + y^2 = 100). This means any point ((x, y)) that meets this equation, such as (10, 0), (0, 10), (-10, 0), and (0, -10), as well as any other points that fall on the circle's perimeter, will lie on the circle. In general, points can be expressed in parametric form as ((10 \cos \theta, 10 \sin \theta)) for any angle (\theta).
The radius