n=100
{[(n/4)-1]*n}+(n/2)
={[(100/4)-1]*100}+(100/2)
={[25-1]*100}+50
={24*100}+50
=2400+50
=2450
2, 4, 6, 8, 10, 12 and just keep adding 2 until you get to 100.
The even numbers up to 100 are: 2 468101214161820222426283032343638404244464850525456586062646668707274767880828486889092949698100.
even numbers 1-100
16
10100, not sure how you do it other than the incredibly long way of adding every single number but I'm pretty sure thats the answer
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82.84,86,88,90,92,94,96,98,and 100Start with 2 and keep adding 2. JHC!
2, 4, 6, 8, 10, 12 and just keep adding 2 until you get to 100.
Adding up all the even numbers from the first (2) to the fiftieth (100): [(100 + 2) / 2] x 50 = 2550 Can you see the logic of this method?
Adding: 100+44 Multiplying: 12*12
The first 100 even numbers are: 2 468101214161820222426283032343638404244464850525456586062646668707274767880828486889092949698100102104106108110112114116118120122124126128130132134136138140142144146148150152154156158160162164166168170172174176178180182184186188190192194196198200.
The first 100 whole, even numbers are: 2468101214161820222426283032343638404244464850525456586062646668707274767880828486889092949698100102104106108110112114116118120122124126128130132134136138140142144146148150152154156158160162164166168170172174176178180182184186188190192194196198200.
The even numbers up to 100 are: 2 468101214161820222426283032343638404244464850525456586062646668707274767880828486889092949698100.
even numbers 1-100
The sum of the first 100 positive even numbers is 10,100.
Well, for every 10 numbers there are 5 even numbers (2,4,6,8,10). So if you include beginning and ending numbers, the even numbers from from 100 to 150 are:100102104106108110112114116118120122124126128130132134136138140142144146148150
The sum of the first 100 positive even numbers is 10,100.
In Java:System.out.println("Even numbers")for (int i = 2; i