Although you said "cylinder," if you drill a hole through the center of a sphere, the shape of the volume you drill out is not a perfect cylinder. It looks more like a medicine capsule, a cylinder with convex end caps. The volume of a sphere = (4/3)*pi*r3, and the volume of a cylinder = pi*r2*h, where r is the radius and h is the height. So, the volume you're looking for is the volume of the sphere minus the volume of the cylinder minus the volume of the two end caps = (4/3)*pi*r3 - pi*r2*h - volume of the end caps. It requires calculus to determine the volume of the end caps. Keith Devlin of the Mathematical Association of America provides an outstanding explanation of this problem, including the computation of the end caps. See the nearby link. Keith's result is given as 4/3 * h^3. Should be 4/3 * pi * h^3. In other words, the same volume of a sphere of diameter h.
Formula for calculating the area of sphere is : 4 * pi * r * r
A sphere and a cylinder are different shapes. A sphere is like a ball, and a cylinder is like a can.
(4/3)*pi*r^3 pi is constant 3.14, r is radius of the sphere.
They are both 3D shapes and use pi in calculating area or volume
V=4/3*Pi*r3 where r is the radius.
Formula for calculating the area of a hemisphere... Area = (4 x pi x r2) / 2
The formula for calculating the volume of a sphere is 4/3 pi r3. If your sphere has a radius of 3 cm, you can expect it to have a volume of about 113 cubic centimeters.
Volume of a section of a sphere = pi * (h2) * (r - h/3) where pi = 3.14159... h is the distance from the flat base of the section to the apex of the section. r is the radius of the sphere
-- Volume of a sphere = 4/3 x (pi) x (radius)3 -- Volume of a cylinder = (pi) x (radius)2 x (length) The only relationship I can see is that they both involve (pi).
He discovered the relationship between a sphere and a circumscribed cylinder of the same height and diameter. The volume is 4⁄3πr3 for the sphere, and 2πr3 for the cylinder. The surface area is 4πr2 for the sphere, and 6πr2 for the cylinder (including its two bases), where r is the radius of the sphere and cylinder. The sphere has a volume and surface area two-thirds that of the cylinder. A sculpted sphere and cylinder were placed on the tomb of Archimedes at his request.
4/3 *PI* r3 The formula was first derived by Archimedes, who showed that the volume of a sphere is 2/3 that of a circumscribed cylinder.
A sphere has 0 vortex and a cylinder has 2 faces