d(t)=Vi(t)+((1/2)(a*t^2))
I just can't find anywhere to explain where that 1/2 constant comes from.
If the car begins with zero speed, thenDistance = 1/2 (acceleration) x (time)2
There is not enough information to answer the question. The answer depends onis the object travelling at constant velocity?is the acceleration constant?If it is an object travelling with constant acceleration, which three of the following four variables are knows: initaial velocity, final velocity, acceleration and time.
D = 60T where T is expressed in hours.
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
d = 1/2 a t2 where d is distance traveled a is the constant acceleration t is the time You can calculate the value of "a" by dividing "v" by "t".
If the car begins with zero speed, thenDistance = 1/2 (acceleration) x (time)2
There is not enough information to answer the question. The answer depends onis the object travelling at constant velocity?is the acceleration constant?If it is an object travelling with constant acceleration, which three of the following four variables are knows: initaial velocity, final velocity, acceleration and time.
D = 60T where T is expressed in hours.
No. Acceleration is the rate at which the speed is INCREASING. Since the speed is increasing,the distance traveled by the body in each time interval is also increasing.
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
No. The total distance traveled divided by constant speed is the time interval.
Acceleration=Speed1-speed2/Distance traveled
You can only know the distance for sure if acceleration or deceleration is constant. Add the start and end velocities and divide by two and then multiply by the time to get your distance.
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
an increasing distance is traveled during each unit of time
If an object is traveling at a constant velocity, its acceleration is 0. Even if it traveled for 2 years.