Σ(2n-1)
147, 149, 151, 153 Procedure Assume the numbers are 2x-3, 2x-1, 2x+1, 2x+3 ........................ (1) the summation = 8 x = 600 so, x = 75 Substitute the value of x in (1) to get the answer above
Answer55, 57, 59, 61, 63, 65DetailsAssume the numbers are 2x-5, 2x-3, 2x-1, 2x+1, 2x+3 , 2x +5 ........................ (1)the summation = 12 x = 360so, x = 30Substitute the value of x in (1) to get the answer above
There is a surprisingly easy formula for this. Sum of n odd numbers = n2 So the sum of the first 600 odd numbers (starting with 1 as the very first odd number) is 6002 = 360000.
It depends on what you are adding.
That means to add all the numbers together.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2.
Yes, the factors of all odd numbers are odd numbers.
The set of odd numbers is an arithmetic sequence. Let say that the sequence has n odd numbers where the first term is a1 and the last one is n. The formula to find the sum on nth terms for an arithmetic sequence is: Sn = (n/2)(a1 + an) or Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference that for odd numbers is 2. Sn = (n/2)(2a1 + 2n - 2)
The sum of two odd numbers is always even; the sum of three odd numbers is always odd; the sum of four odd numbers is always even; the sum of five odd numbers is always odd; etc
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You cannot. The sum of 5 odd numbers must be odd. 30 is not odd.You cannot. The sum of 5 odd numbers must be odd. 30 is not odd.You cannot. The sum of 5 odd numbers must be odd. 30 is not odd.You cannot. The sum of 5 odd numbers must be odd. 30 is not odd.
odd numbers