Σ(2n-1)
147, 149, 151, 153 Procedure Assume the numbers are 2x-3, 2x-1, 2x+1, 2x+3 ........................ (1) the summation = 8 x = 600 so, x = 75 Substitute the value of x in (1) to get the answer above
Answer55, 57, 59, 61, 63, 65DetailsAssume the numbers are 2x-5, 2x-3, 2x-1, 2x+1, 2x+3 , 2x +5 ........................ (1)the summation = 12 x = 360so, x = 30Substitute the value of x in (1) to get the answer above
It depends on what you are adding.
That means to add all the numbers together.
There is a surprisingly easy formula for this. Sum of n odd numbers = n2 So the sum of the first 600 odd numbers (starting with 1 as the very first odd number) is 6002 = 360000.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2.
Yes, the factors of all odd numbers are odd numbers.
The set of odd numbers is an arithmetic sequence. Let say that the sequence has n odd numbers where the first term is a1 and the last one is n. The formula to find the sum on nth terms for an arithmetic sequence is: Sn = (n/2)(a1 + an) or Sn = (n/2)[2a1 + (n - 1)d] where d is the common difference that for odd numbers is 2. Sn = (n/2)(2a1 + 2n - 2)
The sum of two odd numbers is always even; the sum of three odd numbers is always odd; the sum of four odd numbers is always even; the sum of five odd numbers is always odd; etc
To find the sum of all odd numbers from 1 to 499, we can use the formula for the sum of an arithmetic series. The formula is n/2 * (first term + last term), where n is the number of terms. In this case, there are 250 odd numbers from 1 to 499. So, the sum would be 250/2 * (1 + 499) = 125 * 500 = 62,500.
26
There are 37 odd numbers from 1 to 73. Odd numbers are integers that are not divisible by 2, and they alternate with even numbers. In this case, the odd numbers from 1 to 73 are 1, 3, 5, ..., 71, 73. To count them, you can use the formula (last number - first number)/2 + 1 = (73-1)/2 + 1 = 36 + 1 = 37.