For a pulley, it is driver RPM x driver diameter = driven RPM x driven diameter. Keep in mind that the diameter you should use is the diameter where the belt is riding in the pulley. For instance, an A belt in an AB pulley will ride lower in the pulley than it would in an A pulley. For sprockets, the formula is the same, but replace the diameter with # teeth. It looks like this. driver rpm x # teeth of driver sprocket = driven RPM x # teeth of driven sprocket
according to velocity ratio i.e N1/N2 = D2/D1 which implies that diameter of gear is inversly proportaional to speed . hence, DRIVEN GEAR will move faster as it is smaller in size than the DRIVING GEAR
Menu-driven simply means you execute the application's commands by selecting them from a menu, as opposed to command-driven whereby you enter (type) the commands manually.
write a note on event driven programming
You can find the source code of the menu driven graphics program here: http://www.start2code.com/Cresources/menu-driven-graphics-program-c.html
Develop a menu driven proramming in C++ on Examination System ?
calculating sprocket RPM is very easy if you know what the RPM of the drive sprocket is. If you know that then it is a simple fraction problem. If you make the drive gear the numerator or the top part of the fraction and the driven gear the denominator or the bottom part of the fraction (DRIVE/DRIVEN) I.E. if the drive sprocket has 25 teeth and your driven sprocket has 100 teeth (25/100) that will reduce to (1/4) or a 4:1 ratio. So if your drive sprocket is spinning at 1000 RPM then your driven sprocket will be spinning at 250 RPM. You can plug your specific sprocket tooth count into that equation and come up with the right answer.
Think about your ten speed bicycle. The bike is in the lowest gear when the front sprocket is on the smallest diameter and the rear is on the largest. On the contrary, when the bike is at high speed, the rear is on the small diameter sprocket and the front is on the large diameter sprocket. Therefore, increasing the drive pulley size will increase the driven pulley speed (assuming the drive pulley stays at the same RPM). Similarly, increasing the driven pulley size will result in a slower speed (again, assuming the drive pulley stays at the same RPM).
More teeth in the front sprocket and less teeth in the back sprocket. You can also add performance exhaust, and take the governor out.
More teeth in the front sprocket and less teeth in the back sprocket. You can also add performance exhaust, and take the governor out.
The bora v5 does not have a cam belt. It has two timing chains. The first is driven by a sprocket on the crankshaft. This first chain drives a sprocket connected to a smaller sprocket on a common shaft. This smaller sprocket drives the camshaft chain which drives the twin cam shafts. Both chains have tensioners.
Basically it's inside the oil pan at the front of the car, by the crankshaft sprocket. It is driven by the crankshaft.
A formula that is used fir driven piles
I have a "Clymer Honda CB 750 Nighthawk 1991-1993 & 1995-1999" book. It says for sprocket sizes, "Drive Sprocket 15 teeth, Driven Sprocket 38 teeth". Nothing else listed in there or in the Owner's Manual as to size.
There are four steps on how to measure pulley size. One of the step-by-step instructions is to diameter of driven pulley) times (revolutions of driven pulley) divided by (revolutions of driven pulley) equals (diameter of driver pulley).
On a bike there's one(or more) front sprocket(s) by the pedals connected by a chain to one(or more) rear sprocket(s) by the rear wheel. As the wheel isn't driven directly by the pedals, and there's usually a difference in size between the front & rear sprocket this constitutes a gear.
You would use a 5 inch sheave.
Cam gears are also refered to as sprockets (just another name). A chain or belt that is driven by a crankshaft gear/sprocket turns the cam gear(s)/sprocket(s). In certain high performance applications there is no chain, there are just gears meshing but that is probably not relevant to your question.