The current [I] (measured in Amps) is equal to the power [P] (measured in Watts) divided by the voltage [V] (in Volts).
I = P/V
Amps = Watts / Volts
Therefore,
P*V=I
Watts * Volts = Amps
There are two important formulas when calculating Voltage, Current, Resistance and wattage. Ohm's Law states that Voltage = Current x Resistance; and Watts = Current x Voltage x PF, where PF is the power factor and has a value from zero to 1. For a purely resistive load the PF is 1 so the formula is simplified to Watts = Current x Voltage. PF decreases for loads like motors or lights with ballasts.
A Mho or Siemens
ohms is the unit of resistance while volts is the unit of voltage
Ohms Law is used for the measurement of resistance. You can find the resistance in a series circuit using this equation; amps=volts/resistance or volts=amps x resistance.The Power Law is used to find the wattage in the circuit. You can find the amount of watts using this equation: watts=volts x amps.CommentOhm's Law has nothing whatsoever to do with either resistance or power.The equation, R = E/I, is derived from the definition of the ohm, and not from Ohm's Law.Ohm's Law simply describes a linear relationship between the potential difference across a conductor and the current through it. It does NOT describe the relationship between potential difference, current, and resistance.
Internal resistance
Ohms law is: I = V / R (current = voltage / resistance)... where if the voltage or resistance changes then the current will change. ... the current and resistance is a inversely proportional linearly relationship ...this means that if the resistance doubles then the current halfs, if the resistance halfs then the current doubles, etc...hope this helps
Current is inversely proportional to resistance. If you double the resistance, you halve the current. Ohm's Law: Volts = Amps * Ohms Solve for Amps: Amps = Volts / Ohms
The relationship is given by Ohm's Law:V = IR (voltage = current x resistance) In SI units: Volts = amperes x ohms
Amperes does not convert into volts they are two different values. Become familiar with the following formula and look at the relationships between the values. Volts = Amps x Resistance, Amps = Volts / Resistance and Resistance = Volts / Amps.
ohms is the unit of resistance while volts is the unit of voltage
Ohms Law is used for the measurement of resistance. You can find the resistance in a series circuit using this equation; amps=volts/resistance or volts=amps x resistance.The Power Law is used to find the wattage in the circuit. You can find the amount of watts using this equation: watts=volts x amps.CommentOhm's Law has nothing whatsoever to do with either resistance or power.The equation, R = E/I, is derived from the definition of the ohm, and not from Ohm's Law.Ohm's Law simply describes a linear relationship between the potential difference across a conductor and the current through it. It does NOT describe the relationship between potential difference, current, and resistance.
The resistance of a lamp operating at 115 volts and using 0.25 amp of current is 460. The relationship I used is Ohm's law.
Ohm's LawAnswerIt's not known as anything; it's simply an equation. Ohm's Law describes constant proportionality between current and voltage for certain, but not all, materials (linear or ohmic) -it has nothing to do with this equation.
There is no direct relationship between watts and volts. Watts = volts x current in amps.
Voltage, measured in volts. <><><> This question is derived from the fundamental relationship between electrical components which is known as Ohms Law: V = I x R where V = voltage (Volts), I = current (Amps) and R= resistance (Ohms).
Internal resistance
The relationship between amperes, volts, and watts is... watts = amperes * volts Confirming by looking at the fundamental units involved... watts (joules per second) = amperes (coulombs per second) * volts (joules per coulomb)
The relationship between amperes, volts, and watts is... watts = amperes * volts Confirming by looking at the fundamental units involved... watts (joules per second) = amperes (coulombs per second) * volts (joules per coulomb)
It requires the ability to multiply and divide. It requires the ability to mentally separate voltage from current and to understand resistance and when to add resistance for series circuits and worse identify and calculate parallel loads.