If the frequency of genotype AA is p^2, where p is the frequency of allele A, then the frequency of genotype AA would be p^2.
F = 1-observed frequency(Aa)/expected frequency(Aa)
If the male parent has genotype AS and the female parent has genotype AA what is the offspring?
The Hardy-Weinberg Equilibrium equation: p2 + 2pq + q2 = 1 p is frequency of dominant allele A q is frequency of recessive allele a p + q always equals 1 pp or p2 is probability of AA occurring qq or q2 is probability of AA occurring 2pq is probability of Aa occurring (pq is probability of Aa, qp is probability of aA, so 2pq is probability of all heterozygotes Aa) These add up to 1 because they represent all possibilities. The frequency of the homozygous recessive genotype
Heterozygotes. If AA X AA, or AA X AA, is all the mating allowed, then Aa will lose frequency in the population.
If you have the alleles A and a, then the The hardy-weinberg equation is: A2 + 2Aa + a2 = 1 where a and A represent allele frequencies. So A2 would be the genotype frequency for AA. 2Aa is the genotype frequency for Aa. And a2 is the genotype frequency for aa. Plug in whatever information you have into the equation and you can probably come up with an answer. Save
50% AA and 50% Aa
No because AA and SS create the genotype AS :)
i think they represent if you have dominant or recessive traits. For example a symbol for a genotype may be AA or Aa.
A genotype is decided from two alleles. One of these alleles comes from the father, and one comes from the mother. Thus it should be clear that the genotype can be different from both parents. For instance, suppose the father has genotype AA, and the mother has genotype aa. In this case, the child will have genotype Aa, which neither parent has.
If A represents a dominant allele, then the AA genotype would produce the dominant phenotype.
The offspring's genotype will be AA. Both parents are homozygous dominant, AA, having only dominant alleles to pass on to their offspring. So each parent can pass on only the dominant allele (A) to its offspring. So the offspring will also be homozygous dominant, AA.
the equation you would use would be Aa=2pq