2941176470.589 Hz or 2941.1764706 MHz or 2.9412GHz
The energy of one photon of microwave radiation with a 12.0 cm wavelength can be calculated using the formula E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. First, convert the wavelength to meters (0.12 m) and then plug the values into the formula to find the energy of one photon.
Energy (E) of photons of electromagnetic radiation is given by Planck's equation ..E = hf .. h = Planck constant (6.625^-34 Js), f = frequency (Hz)So E is proportional to frequency .. radiation with the highest frequency is Gamma
The speed of a wave is calculated by multiplying its wavelength by its frequency. In this case, the speed would be 340 m/s.
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant (6.63 x 10^-34 J.s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Plugging in the values, we get E = (6.63 x 10^-34 J.s * 3.00 x 10^8 m/s) / 0.122 m = approximately 1.63 x 10^-24 J. So, the energy of one photon of microwave radiation with a wavelength of 0.122m is approximately 1.63 x 10^-24 Joules.
You need to use the equation c= wavelength * frequency , where c is the speed of light (2.99792458 * 108 m/s) Solve the equation for frequency, frequency=c/wavelength frequency = 1.02 * 1016 s-1 or the unit could be Hz which equals 1 s-1
The energy of one photon of microwave radiation with a 12.0 cm wavelength can be calculated using the formula E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. First, convert the wavelength to meters (0.12 m) and then plug the values into the formula to find the energy of one photon.
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the radiation. Plugging in the values, we find that the energy of one photon of microwave radiation with a wavelength of 0.158 m is approximately 1.25 x 10^-24 J.
Energy (E) of photons of electromagnetic radiation is given by Planck's equation ..E = hf .. h = Planck constant (6.625^-34 Js), f = frequency (Hz)So E is proportional to frequency .. radiation with the highest frequency is Gamma
The speed of a wave is calculated by multiplying its wavelength by its frequency. In this case, the speed would be 340 m/s.
Wavelength = (speed) / (frequency)= (3 x 108) / (4.32 x 1020) = 6.94 x 10-13 meter = 6.94 x 10-4 nanometers
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant (6.63 x 10^-34 J.s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Plugging in the values, we get E = (6.63 x 10^-34 J.s * 3.00 x 10^8 m/s) / 0.122 m = approximately 1.63 x 10^-24 J. So, the energy of one photon of microwave radiation with a wavelength of 0.122m is approximately 1.63 x 10^-24 Joules.
The amount of energy is inversely related to the wavelength of the radiation: the shorter the wavelength, the greater the energy of each photon.This was originally discovered by Max Planck who identified a co-effiecient of proportionality that related a photon's energy to its frequency. This co-effiecient is known as the Planck constant and allows the energy of a photon to be found using the following relation (known as the Planck relation or the Planck-Einstein equation):E = hv (Eq. 1)Where:E = Energy (J)h = Planck constant (6.62606896×10−34 Js)v = frequency (Hz).For electromagnetic radiation travelling through a vacuum:v = c / λ(Eq. 2)Where:c = speed of light in a vacuumλ = wavelength (m)As such this can be substituted into the Planck relation to give the following: E = hc / λ(Eq. 3)From equations 1 and 3 it can be seen that a photon's energy is directly proportional to it's frequency and inversely proportional to its wavelength.
You need to use the equation c= wavelength * frequency , where c is the speed of light (2.99792458 * 108 m/s) Solve the equation for frequency, frequency=c/wavelength frequency = 1.02 * 1016 s-1 or the unit could be Hz which equals 1 s-1
The speed of light is fixed and so the wavelength and the frequency of light are related like this:wavelength * frequency = speed of lightYou just have to be careful your units match up. Often wavelengths of light are listed in nanometers, or nm, while the speed of light is often given in meters per second, or m/s. Make sure everything is in terms of meters or your answer will be way off. Frequency is almost always given in terms of 1/seconds, which is also called a Hertz. See the Web Links for more information about the electromagnetic spectrum.
assuming the wave is electromagnetic... the energy of a single photon of that frequency is given by the formula E=hf where E= energy of the photon h=the Planck constant f= the frequency of the photon From this the energy of the photon is the Planck constant (6.63 x10-34) multiplied by the frequency 3.6x1016 Hz. E= 23.9x10-18 Joules. The wavelength of any wave is determined by the equation wave speed = frequency x wavelength. thus, the wavelength is the wave speed divided by the frequency. since all electromagnetic waves travel at the speed of light then... wavelength = 3x108 / 3.6x1016 wavelength = 0.83x10-8 = 8.3x10-9 metres. The electromagnetic radiation corresponding to this energy and wavelength is ultraviolet radiation and may be of interest to nuclear medicine.
We have an equation for that: lambda = c / (f * sqrt(epsilon)) where lambda = wavelength in [m] c = the speed of light in vacuum = 3E+8 [m/s] epsilon = the dielectric constant of the medium in question = 1 for air or vacuum Hence, the photon frequency in air or vacuum = c / lambda = 3x108 / 0.21 [s-1] = 1.43 [GHz]. The photon energy, E = h * f, where h = Planck's constant = 6.63x10-34 [Js]. E = 6.63x10-34 [Js] * 1.43 [GHz] = 9.5x10-34 [J]
The energy of a photon can be calculated using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values, we get E = (6.626 x 10^-34 J*s * 3 x 10^8 m/s) / 125m, which gives us the energy of one photon of microwave radiation.