The energy of one photon of microwave radiation with a 12.0 cm wavelength can be calculated using the formula E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. First, convert the wavelength to meters (0.12 m) and then plug the values into the formula to find the energy of one photon.
Gamma rays have the highest level of energy among all forms of electromagnetic radiation. This can be determined by looking at their position on the electromagnetic spectrum, where they have the shortest wavelength and highest frequency.
The speed of a wave is calculated by multiplying its wavelength by its frequency. In this case, the speed would be 340 m/s.
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant (6.63 x 10^-34 J.s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Plugging in the values, we get E = (6.63 x 10^-34 J.s * 3.00 x 10^8 m/s) / 0.122 m = approximately 1.63 x 10^-24 J. So, the energy of one photon of microwave radiation with a wavelength of 0.122m is approximately 1.63 x 10^-24 Joules.
You need to use the equation c= wavelength * frequency , where c is the speed of light (2.99792458 * 108 m/s) Solve the equation for frequency, frequency=c/wavelength frequency = 1.02 * 1016 s-1 or the unit could be Hz which equals 1 s-1
The energy of one photon of microwave radiation with a 12.0 cm wavelength can be calculated using the formula E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. First, convert the wavelength to meters (0.12 m) and then plug the values into the formula to find the energy of one photon.
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the radiation. Plugging in the values, we find that the energy of one photon of microwave radiation with a wavelength of 0.158 m is approximately 1.25 x 10^-24 J.
Gamma rays have the highest level of energy among all forms of electromagnetic radiation. This can be determined by looking at their position on the electromagnetic spectrum, where they have the shortest wavelength and highest frequency.
The speed of a wave is calculated by multiplying its wavelength by its frequency. In this case, the speed would be 340 m/s.
The wavelength of gamma ray electromagnetic radiation with a frequency of 2.73 × 10^20 Hz is approximately 1.10 × 10^-12 meters.
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant (6.63 x 10^-34 J.s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Plugging in the values, we get E = (6.63 x 10^-34 J.s * 3.00 x 10^8 m/s) / 0.122 m = approximately 1.63 x 10^-24 J. So, the energy of one photon of microwave radiation with a wavelength of 0.122m is approximately 1.63 x 10^-24 Joules.
The amount of energy is inversely related to the wavelength of the radiation: the shorter the wavelength, the greater the energy of each photon.This was originally discovered by Max Planck who identified a co-effiecient of proportionality that related a photon's energy to its frequency. This co-effiecient is known as the Planck constant and allows the energy of a photon to be found using the following relation (known as the Planck relation or the Planck-Einstein equation):E = hv (Eq. 1)Where:E = Energy (J)h = Planck constant (6.62606896×10−34 Js)v = frequency (Hz).For electromagnetic radiation travelling through a vacuum:v = c / λ(Eq. 2)Where:c = speed of light in a vacuumλ = wavelength (m)As such this can be substituted into the Planck relation to give the following: E = hc / λ(Eq. 3)From equations 1 and 3 it can be seen that a photon's energy is directly proportional to it's frequency and inversely proportional to its wavelength.
The equations for wavelength and frequency of light are: Wavelength (λ) = c / f, where c is the speed of light (3.00 × 10^8 m/s) and f is the frequency of the light wave. Frequency (f) = c / λ, where c is the speed of light and λ is the wavelength of the light wave.
You need to use the equation c= wavelength * frequency , where c is the speed of light (2.99792458 * 108 m/s) Solve the equation for frequency, frequency=c/wavelength frequency = 1.02 * 1016 s-1 or the unit could be Hz which equals 1 s-1
The energy of a wave is given by E = h*f, where h is Planck's constant (approx. 6.63 x 10^-34 Joule seconds). So, the energy of a wave with frequency 3.6 x 10^16 Hz is approximately 2.38 x 10^-17 Joules. The wavelength can be calculated using the formula λ = c/f, where c is the speed of light (approx. 3 x 10^8 m/s), giving a wavelength of approximately 8.33 x 10^-9 meters. This falls into the ultraviolet range, which is not typically used in nuclear medicine procedures.
To calculate the energy of a photon, you can use the formula E = hc/λ, where E is energy, h is Planck's constant (6.626 x 10^-34 J∙s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the photon in meters. Converting 21 cm to meters (0.21 m) and plugging in the values, the energy of the microwave photon would be approximately 9.48 x 10^-24 joules.
The energy of a photon can be calculated using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values, we get E = (6.626 x 10^-34 J*s * 3 x 10^8 m/s) / 125m, which gives us the energy of one photon of microwave radiation.